A231347 Triangle read by rows: T(n,k), n>=1, k>=1, in which column k lists the odd numbers interleaved with k-1 zeros but T(n,1) = n - 1 and the first element of column k is in row k(k+1)/2.
0, 1, 2, 1, 3, 0, 4, 3, 5, 0, 1, 6, 5, 0, 7, 0, 0, 8, 7, 3, 9, 0, 0, 1, 10, 9, 0, 0, 11, 0, 5, 0, 12, 11, 0, 0, 13, 0, 0, 3, 14, 13, 7, 0, 1, 15, 0, 0, 0, 0, 16, 15, 0, 0, 0, 17, 0, 9, 5, 0, 18, 17, 0, 0, 0, 19, 0, 0, 0, 3, 20, 19, 11, 0, 0, 1, 21, 0, 0, 7, 0, 0
Offset: 1
Examples
Triangle begins: 0; 1; 2, 1; 3, 0; 4, 3; 5, 0, 1; 6, 5, 0; 7, 0, 0; 8, 7, 3; 9, 0, 0, 1; 10, 9, 0, 0; 11, 0, 5, 0; 12, 11, 0, 0; 13, 0, 0, 3; 14, 13, 7, 0, 1; 15, 0, 0, 0, 0; 16, 15, 0, 0, 0; 17, 0, 9, 5, 0; 18, 17, 0, 0, 0; 19, 0, 0, 0, 3; 20, 19, 11, 0, 0, 1; 21, 0, 0, 7, 0, 0; 22, 21, 0, 0, 0, 0; 23, 0, 13, 0, 0, 0; ... For n = 15 the aliquot divisors of 15 are 1, 3, 5, therefore the sum of aliquot divisors of 15 is 1 + 3 + 5 = 9. On the other hand the 15th row of triangle is 14, 13, 7, 0, 1, hence the alternating row sum is 14 - 13 + 7 - 0 + 1 = 9, equalling the sum of aliquot divisors of 15. If n is even then the alternating sum of the n-th row of triangle is simpler than the sum of aliquot divisors of n. Example: the sum of aliquot divisors of 24 is 1 + 2 + 3 + 4 + 6 + 8 + 12 = 36, and the alternating sum of the 24th row of triangle is 23 - 0 + 13 - 0 + 0 - 0 = 36.
Crossrefs
Formula
T(n,1) = n - 1.
T(n,k) = A196020(n,k), for k >= 2.
Comments