A232013 Number of iterations of A176341 ("position of n in Pi") until a value is reached for the second time, when starting with n, or -1 if no value is repeated.
4, 1, 12, 4, 13, 14, 11, 10
Offset: 0
Examples
a(0)=4 since A176341(0)=32 (position of the first "0" in Pi's digits), A176341(32)=15 (position of the first "32" in Pi's digits), A176341(15)=3 (position of the first "15" in Pi's digits), A176341(3)=0 (position of the first "3" in Pi's digits); here we find the "0" again after 4 iterations, thus a(0)=4. a(1)=1 since A176341(1)=1 (the first "1" occurs at position 1 in Pi's digits), which already "closes the loop" after 1 iteration. a(2)=12 because the iterations yield 2 > 6 > 7 > 13 > 110 > 174 > 155 > 314 > 0 > 32 > 15 > 3 > 0, here we re-enter the loop (of length 4) after 12 iterations.
Links
- David G. Andersen, Loop Sequences within Pi, on The Pi-Search Page (Search 2*10^8 decimal digits of Pi).
- Hans Havermann, Information table of n, a(n) for n=0..100.
- Joaquin Navarro, Les secrets du nombre Pi (Book review, in French).
- James Taylor, Irrational Numbers Search Engine (Search 2*10^9 decimal digits of Pi).
- Ady Tzidon, Loops in Pi.
Programs
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Mathematica
pidigits = First[RealDigits[N[Pi, 10^6]]]; Table[ lst = {}; test = n; steps = 1; While[AppendTo[lst, test]; ! MemberQ[lst, test = First[ First[SequencePosition[pidigits, IntegerDigits[test], 1]]] - 1], steps++ ]; steps, {n, 0, 7}] (* Robert Price, Aug 31 2019 *)
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PARI
A232013(n)={my(u=0);for(i=1,9e9,u+=1<
A176341(n))&&return(i))}
Extensions
Edited by Hans Havermann, Aug 01 2014
Comments