A232701 a(n) = (2*n-1)!! mod n!, where double factorial is A006882.
0, 1, 3, 9, 105, 315, 4095, 11025, 348705, 1545075, 17931375, 93087225, 3764185425, 45589819275, 1060569885375, 15877899662625, 900941666625, 5722531807867875, 90088576482279375, 1688777976676415625, 18148954872023600625, 320586579951629866875, 11054393914490520969375
Offset: 1
Keywords
Examples
a(4) = 1*3*5*7 mod (1*2*3*4) = 105 mod 24 = 9.
Programs
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Mathematica
o = 1; Reap[For[n = 1, n <= 99, n += 2, o *= n; m = Mod[o, (Quotient[n, 2] + 1)!]; Sow[m]]][[2, 1]] (* Jean-François Alcover, Oct 05 2017, translated from Alex Ratushnyak's Python code *)
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Python
import math o=1 for n in range(1,99,2): o*=n print(o % math.factorial(n//2+1), end=', ')
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