A239933 Triangle read by rows in which row n lists the parts of the symmetric representation of sigma(4n-1).
2, 2, 4, 4, 6, 6, 8, 8, 8, 10, 10, 12, 12, 14, 6, 6, 14, 16, 16, 18, 12, 18, 20, 8, 8, 20, 22, 22, 24, 24, 26, 10, 10, 26, 28, 8, 8, 28, 30, 30, 32, 12, 16, 12, 32, 34, 34, 36, 36, 38, 24, 24, 38, 40, 40, 42, 42, 44, 16, 16, 44, 46, 20, 46, 48, 12, 12, 48, 50, 18, 20, 18, 50, 52, 52, 54, 54, 56, 20, 20, 56, 58, 14, 14, 58, 60, 12, 12, 60, 62, 22, 22, 62, 64, 64
Offset: 1
Examples
The irregular triangle begins: 2, 2; 4, 4; 6, 6; 8, 8, 8; 10, 10; 12, 12; 14, 6, 6, 14; 16, 16; 18, 12, 18; 20, 8, 8, 20; 22, 22; 24, 24; 26, 10, 10, 26; 28, 8, 8, 28; 30, 30; 32, 12, 16, 12, 32; ... Illustration of initial terms in the third quadrant of the spiral described in A239660: . _ _ _ _ _ _ _ _ . | | | | | | | | | | | | | | | | . | | | | | | | | | | | | | | |_|_ _ . | | | | | | | | | | | | | | 2 |_ _| . | | | | | | | | | | | | |_|_ 2 . | | | | | | | | | | | | 4 |_ . | | | | | | | | | | |_|_ _ |_ _ _ _ . | | | | | | | | | | 6 |_ |_ _ _ _| . | | | | | | | | |_|_ _ _ |_ 4 . | | | | | | | | 8 | |_ _ | . | | | | | | |_|_ _ _ |_ | |_ _ _ _ _ _ . | | | | | | 10 | |_ |_ |_ _ _ _ _ _| . | | | | |_|_ _ _ _ |_ _ 8 |_ _| 6 . | | | | 12 | |_ | . | | |_|_ _ _ _ _ |_ _ | |_ _ _ _ _ _ _ _ . | | 14 | | |_ |_ _ |_ _ _ _ _ _ _ _| . |_|_ _ _ _ _ | |_ _ |_ | 8 . 16 | |_ _ | | | . | |_|_ |_ _ |_ _ _ _ _ _ _ _ _ _ . |_ _ 6 |_ _ | |_ _ _ _ _ _ _ _ _ _| . | |_ | | 10 . |_ 6 | |_ _ | . |_ |_ _ _| |_ _ _ _ _ _ _ _ _ _ _ _ . |_ _ | |_ _ _ _ _ _ _ _ _ _ _ _| . | | 12 . |_ _ _ | . | |_ _ _ _ _ _ _ _ _ _ _ _ _ _ . | |_ _ _ _ _ _ _ _ _ _ _ _ _ _| . | 14 . | . |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ . |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _| . 16 . For n = 7 we have that 4*7-1 = 27 and the 27th row of A237593 is [14, 5, 3, 2, 1, 2, 2, 1, 2, 3, 5, 14] and the 26th row of A237593 is [14, 5, 2, 2, 2, 1, 1, 2, 2, 2, 5, 14] therefore between both Dyck paths there are four regions (or parts) of sizes [14, 6, 6, 14], so row 7 is [14, 6, 6, 14]. The sum of divisors of 27 is 1 + 3 + 9 + 27 = A000203(27) = 40. On the other hand the sum of the parts of the symmetric representation of sigma(27) is 14 + 6 + 6 + 14 = 40, equaling the sum of divisors of 27.
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