A242319 Number of length n+4+2 0..4 arrays with every value 0..4 appearing at least once in every consecutive 4+3 elements, and new values 0..4 introduced in order.
140, 440, 1300, 3648, 10012, 27368, 75236, 208976, 577964, 1596216, 4408020, 12176768, 33645500, 92967176, 256849892, 709617776, 1960543660, 5416680632, 14965468916, 41347189280, 114235439996, 315613828040, 871989852740
Offset: 1
Keywords
Examples
Some solutions for n=5 ..0....0....0....0....0....0....0....0....0....0....0....0....0....0....0....0 ..1....1....1....1....1....1....1....0....1....1....1....0....0....1....1....1 ..0....2....2....2....0....0....1....1....2....2....2....1....1....0....2....2 ..2....1....2....3....2....2....2....2....3....2....0....2....2....2....0....0 ..3....3....3....3....3....3....3....2....1....3....3....1....0....3....3....3 ..2....0....4....0....4....0....4....3....4....4....4....3....3....2....4....1 ..4....4....1....4....0....4....0....4....0....1....1....4....4....4....1....4 ..3....1....0....2....0....1....2....0....3....0....0....2....1....1....2....0 ..1....2....2....1....1....2....1....1....2....1....2....0....2....0....0....0 ..0....2....0....4....2....0....2....2....1....2....3....4....2....0....1....2 ..3....1....4....4....0....3....4....3....1....4....0....1....4....4....4....3
Links
- R. H. Hardin, Table of n, a(n) for n = 1..210
Formula
Empirical: a(n) = a(n-1) +2*a(n-2) +4*a(n-3) +6*a(n-4) +10*a(n-5) +12*a(n-6) -4*a(n-7) -6*a(n-8) -6*a(n-9) -2*a(n-11) -2*a(n-12) +a(n-14) +a(n-15)
Comments