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A242392 Irregular table which shows in row n the list of distinct integer arithmetic means of distinct divisors of n, or zero if n <= 2.

%I A242392 #11 May 16 2014 16:03:04
%S A242392 0,0,2,3,3,2,3,4,4,3,5,6,2,5,6,3,6,6,2,3,4,5,6,7,8,7,4,8,2,3,4,5,5,6,
%T A242392 7,8,7,4,8,2,3,4,6,8,9,10,3,5,6,7,8,9,9,2,4,5,6,7,8,9,10,12,10,3,5,6,
%U A242392 7,9,10,11,12,15,2,4,5,8,12,14,6,9,12,12
%N A242392 Irregular table which shows in row n the list of distinct integer arithmetic means of distinct divisors of n, or zero if n <= 2.
%e A242392 Table starts:
%e A242392 0,
%e A242392 0,
%e A242392 2,
%e A242392 3,
%e A242392 3,
%e A242392 2, 3, 4,
%e A242392 4,
%e A242392 3, 5, 6,
%e A242392 2, 5, 6,
%e A242392 3, 6,
%e A242392 6,
%e A242392 2, 3, 4, 5, 6, 7, 8,
%e A242392 7,
%e A242392 4, 8,
%e A242392 2, 3, 4, 6, 8, 9, 10,
%e A242392 3, 5, 6, 7, 8, 9,
%e A242392 9,
%e A242392 2, 4, 5, 6, 7, 8, 9, 10, 12,
%e A242392 10,
%e A242392 3, 5, 6, 7, 9, 10, 11, 12, 15,
%e A242392 2, 4, 5, 8, 12, 14,
%e A242392 6, 9, 12,
%e A242392 12.
%e A242392 2, 3, 4, are in 6th row because:
%e A242392 1) (n/6 + n/2)/2 = (6/6 + 6/2)/2 = (1 + 3)/2 = 2,
%e A242392 2) (n/6 + n/3 + n/2 + n/1)/4 = (6/6 + 6/3 + 6/2 + 6/1)/4 = (1 + 2 + 3 + 6)/4 = 3,
%e A242392 3) (n/3 + n/1)/2 = (6/3 + 6/1)/2 = (2 + 6)/2 = 4.
%Y A242392 Cf. A027750.
%K A242392 nonn,tabf
%O A242392 1,3
%A A242392 _Ilya Lopatin_ and _Juri-Stepan Gerasimov_, May 12 2014