A244797 Number of moduli m such that (prime(n) mod m) = 2.
0, 0, 1, 1, 2, 1, 3, 1, 3, 3, 1, 3, 3, 1, 5, 3, 3, 1, 3, 3, 1, 3, 4, 3, 3, 5, 1, 7, 1, 3, 3, 3, 7, 1, 5, 1, 3, 3, 7, 5, 3, 1, 7, 1, 7, 1, 3, 3, 8, 1, 7, 3, 1, 3, 7, 5, 3, 1, 5, 5, 1, 3, 3, 3, 1, 11, 3, 3, 7, 1, 7, 7, 3, 3, 3, 3, 5, 3, 7, 3, 3, 1, 7, 1, 3, 8
Offset: 1
Examples
prime(5) = 11 = (2 mod m) for m = 3, 9 so that a(5) = 2.
Links
- Clark Kimberling, Table of n, a(n) for n = 1..1000
Programs
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Mathematica
z = 300; f[n_, m_] := If[Mod[Prime[n], m] == 2, 1, 0]; t = Table[f[n, m], {n, 1, z}, {m, 1, Prime[n]}]; Table[Count[t[[k]], 1], {k, 1, z}] (* A244797 *)
Comments