cp's OEIS Frontend

A245100 Triangle read by rows in which row n lists the parts of the symmetric representation of sigma(n), multiplied by n.

%I A245100 #29 Apr 28 2016 11:34:02
%S A245100 1,6,6,6,28,15,15,72,28,28,120,45,27,45,90,90,66,66,336,91,91,168,168,
%T A245100 120,120,120,496,153,153,702,190,190,840,231,105,105,231,396,396,276,
%U A245100 276,1440,325,125,325,546,546,378,162,162,378,1568,435,435,2160,496,496,2016
%N A245100 Triangle read by rows in which row n lists the parts of the symmetric representation of sigma(n), multiplied by n.
%C A245100 Row sums give A064987.
%C A245100 Since both A000203(n) and A024916(n) have a symmetric representation then both row n and the triangle have can be represented as a symmetric polycube.
%F A245100 T(n,k) = n*A237270(n,k).
%e A245100 The irregular triangle begins:
%e A245100 1;
%e A245100 6;
%e A245100 6, 6;
%e A245100 28;
%e A245100 15, 15;
%e A245100 72;
%e A245100 28, 28;
%e A245100 120;
%e A245100 45, 27, 45;
%e A245100 90, 90;
%e A245100 66, 66;
%e A245100 336;
%e A245100 91, 91;
%e A245100 168, 168;
%e A245100 120, 120, 120;
%e A245100 496;
%e A245100 153, 153;
%e A245100 702;
%e A245100 190, 190;
%e A245100 840;
%e A245100 231, 105, 105, 231;
%e A245100 ...
%e A245100 For n = 9 the parts of the symmetric representation of sigma(9) are [5, 3, 5], so row 9 is [45, 27, 45].
%Y A245100 Cf. A000203, A024916, A064987, A143128, A185283, A196020, A236104, A235791, A237270, A237271, A237591, A237593, A244580.
%K A245100 nonn,tabf
%O A245100 1,2
%A A245100 _Omar E. Pol_, Jul 11 2014