A245346 Sum of digits of n in fractional base 10/3.
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 7, 8, 9
Offset: 0
Examples
In base 10/3 the number 11 is represented by 31 and so a(11) = 3 + 1 = 4.
Links
Programs
-
Mathematica
a[n_] := a[n] = If[n == 0, 0, a[3 * Floor[n/10]] + Mod[n, 10]]; Array[a, 100, 0] (* Amiram Eldar, Aug 04 2025 *)
-
PARI
a(n) = if(n == 0, 0, a(n\10 * 3) + n % 10); \\ Amiram Eldar, Aug 04 2025
-
Sage
# uses [basepqsum from A245355] [basepqsum(10,3,y) for y in [0..200]]
Comments