A245354 Sum of digits of n in fractional base 9/5.
0, 1, 2, 3, 4, 5, 6, 7, 8, 5, 6, 7, 8, 9, 10, 11, 12, 13, 6, 7, 8, 9, 10, 11, 12, 13, 14, 11, 12, 13, 14, 15, 16, 17, 18, 19, 8, 9, 10, 11, 12, 13, 14, 15, 16, 13, 14, 15, 16, 17, 18, 19, 20, 21, 14, 15, 16, 17, 18, 19, 20, 21, 22, 19, 20, 21, 22, 23
Offset: 0
Examples
In base 9/5 the number 11 is represented by 52 and so a(11) = 5 + 2 = 7.
Links
Programs
-
Mathematica
a[n_] := a[n] = If[n == 0, 0, a[4 * Floor[n/9]] + Mod[n, 9]]; Array[a, 100, 0] (* Amiram Eldar, Aug 02 2025 *)
-
PARI
a(n) = if(n == 0, 0, a(n\9 * 4) + n % 9); \\ Amiram Eldar, Aug 02 2025
-
Sage
# uses [basepqsum from A245355] [basepqsum(9,5,y) for y in [0..200]]
Comments