A249689 Numbers k such that A084937(3k) > A084937(3k+1).
16, 65, 91, 1514, 1993, 1994, 2452, 2722, 3047, 3214, 3931, 3957, 4356, 4366, 5191, 5581, 5805, 5806, 7519, 8871, 9228, 9752, 10036, 10037, 10039, 10040, 10963, 10964, 11278, 11279, 12015, 12281, 12595, 12665, 13262, 13618, 13648, 15102, 15103, 18529, 18991
Offset: 1
Keywords
Links
- N. J. A. Sloane, Table of n, a(n) for n = 1..641 (Based on _John P. Linderman_'s computation of a million terms of A084937)
Crossrefs
Cf. A084937
Programs
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AWK
# Using a-file for A084937. awk ' BEGIN {s = 0} NR%3 == 0 { s = $2 } NR%3 == 1 { t = $2 if (s > t) print( (NR-1)/3 ) } ' a084937.txt | awk '{ print NR, $1}' >b249689.txt
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Python
from math import gcd A249689_list, l1, l2, s, b = [], 2, 1, 3, set() for n in range(3,10**4): i = s while True: if not i in b and gcd(i,l1) == 1 and gcd(i,l2) == 1: l2, l1 = l1, i b.add(i) if l2 > l1 and n % 3 == 1: A249689_list.append((n-1)//3) while s in b: b.remove(s) s += 1 break i += 1 # Chai Wah Wu, Dec 12 2014