A254403 -id:A254403 - cp's OEIS frontend

A254400 a(n) = floor(b(n)), where b(n) = b(n-1)^(3/2), b(1) = 2.

2, 2, 4, 10, 33, 193, 2684, 139116, 51888311, 373769884171, 228510656987187971, 109234465617278065859643766, 1141667222716533804555279991265973169394, 38575298818045633410275497202805726438253675072452563405216

Offset: 1

Vaclav Kotesovec, Jan 30 2015

Cf. A254401, A254403, A254405.

Floor[RecurrenceTable[{a[1]==2,a[n]==a[n-1]^(3/2)},a,{n,1,15}]]
Table[Floor[2^((3/2)^(n-1))], {n, 1, 15}]

a(n) = floor(2^((3/2)^(n-1))).

A254404 a(n) = floor(a(n-1)^(3/2)), a(1) = 4.

Original entry on oeis.org

4, 8, 22, 103, 1045, 33781, 6208815, 15470810960, 1924285995519778, 84412046357073810845036, 24524866000840265443624861229739287, 3840696279681724751490160062668766360564070043725605, 238020820035391513516910494940635409432084649486247633125762760898691133120625

Offset: 1

Vaclav Kotesovec, Jan 30 2015

Cf. A254403.

RecurrenceTable[{a[1]==4,a[n]==Floor[a[n-1]^(3/2)]},a,{n,1,15}]

a(n) ~ c^((3/2)^n), where c = 2.4979223179189793375148967824709800001224474904593996103376... .

cp's OEIS Frontend

A254400 a(n) = floor(b(n)), where b(n) = b(n-1)^(3/2), b(1) = 2.

Views

Author

Keywords

Crossrefs

Programs

Mathematica

Formula