cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-9 of 9 results.

A256429 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 6, 11, 16, 41, 106, 211, 416, 941, 2106, 4411, 9316, 20341, 44106, 94111, 201716, 435741, 938606, 2014311, 4330116, 9324641, 20060606, 43122511, 92747016, 199552041, 429222606, 923076211, 1985467416, 4270895441, 9186237106, 19758020411, 42498043816, 91411232341
Offset: 0

Views

Author

Kival Ngaokrajang, Mar 28 2015

Keywords

Comments

Inspired by A255870. But at the higher iterations, the perimeter would be a pentagram instead of a pentagon. See illustration in the links.

Crossrefs

Cf. A255870.

Formula

Conjectures from Colin Barker, Mar 29 2015: (Start)
a(n) = 3*a(n-1)-4*a(n-2)+7*a(n-3)-5*a(n-4) for n>3.
G.f.: -(3*x^2-3*x-1) / ((x-1)*(5*x^3-2*x^2+2*x-1)).
(End)

A256569 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 6, 21, 61, 171, 461, 1181, 2951
Offset: 1

Views

Author

Kival Ngaokrajang, Apr 02 2015

Keywords

Comments

Inspired by A255870. But at the higher iterations, the perimeter would be an irregular polygon instead of a pentagon. The construction rule is vertex to vertex expansion. See illustration in the links.

Crossrefs

A256571 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 6, 21, 56, 131, 281, 556, 1046, 1896, 3346, 5796, 9916, 16806, 28316, 47506, 79476, 132706
Offset: 1

Views

Author

Kival Ngaokrajang, Apr 02 2015

Keywords

Comments

Inspired by A255870. But at the higher iterations, the perimeter is an irregular polygon instead of a pentagon. The construction rule is sides to vertices expansion. See illustration in the links.

Crossrefs

Extensions

a(9) corrected and a(10)-a(15) added by Udo Vieth, Jan 16 2023
a(16)-a(17) added by Udo Vieth, Aug 19 2024

A256582 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 11, 46, 146, 416, 1136, 2776
Offset: 1

Views

Author

Kival Ngaokrajang, Apr 04 2015

Keywords

Comments

Inspired by A255870. But the scale factor is tan(3*Pi/10)/(1+phi) instead of 1/phi.
See illustration in the links.

Crossrefs

A256583 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 11, 66, 336, 1666, 8186
Offset: 1

Views

Author

Kival Ngaokrajang, Apr 04 2015

Keywords

Comments

Inspired by A255870. But the scale factor is (1/phi)^2 instead of 1/phi.
See illustration in the links.

Crossrefs

A256597 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 11, 76, 436, 2441
Offset: 1

Views

Author

Kival Ngaokrajang, Apr 04 2015

Keywords

Comments

Inspired by A255870. But the scale factor is tan(Pi/10) instead of 1/phi.
See illustration in the links.

Crossrefs

A263418 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 6, 21, 51, 106, 201, 361, 626, 1061, 1771, 2926, 4801, 7841, 12766, 20741, 33651, 54546, 88361, 143081, 231626, 374901, 606731, 981846, 1588801, 2570881, 4159926, 6731061, 10891251, 17622586, 28514121, 46137001, 74651426, 120788741, 195440491, 316229566
Offset: 0

Views

Author

Kival Ngaokrajang, Oct 17 2015

Keywords

Comments

Inspired by A255870.

Crossrefs

Programs

  • PARI
    {a=1; print1(a, ", "); for(n=1,100, b=fibonacci(n+3)-2; a=a+5*b; print1 (a, ", "))}
    
  • PARI
    Vec(-(x^3+5*x^2+3*x+1)/((x-1)^2*(x^2+x-1)) + O(x^50)) \\ Colin Barker, Oct 18 2015

Formula

a(0) = 1, for n > 0, a(n) = a(n-1) + 5*(fibonacci(n+3)-2) or a(n) = a(n-1) + 5*A001911(n).
From Colin Barker, Oct 18 2015: (Start)
a(n) = 3*a(n-1)-2*a(n-2)-a(n-3)+a(n-4) for n>3.
G.f.: -(x^3+5*x^2+3*x+1) / ((x-1)^2*(x^2+x-1)).
(End)
a(n) = -14 + 2^(-1-n)*((25-11*sqrt(5))*(1-sqrt(5))^n + (1+sqrt(5))^n*(25+11*sqrt(5))) - 10*(1+n). - Colin Barker, Mar 12 2017

A263419 a(n) is the total number of pentagrams in a variant of pentagram fractal after n iterations.

Original entry on oeis.org

1, 6, 11, 26, 51, 106, 201, 396, 751, 1446, 2741
Offset: 0

Views

Author

Kival Ngaokrajang, Oct 17 2015

Keywords

Comments

Inspired by A255870, also same as A263418 but overlaps are prohibited.

Crossrefs

A256107 Irregular triangle read by rows, T(n,k) is the number of pentagrams on the k layers at n iterations of a pentagram fractal (see comment).

Original entry on oeis.org

1, 2, 4, 1, 7, 2, 2, 12, 4, 5, 2, 1, 20, 7, 10, 4, 2, 2, 33, 12, 18, 8, 4, 4, 2, 1, 54, 20, 31, 14, 7, 8, 4, 2, 2, 88, 33, 52, 24, 12, 14, 8, 4, 4, 2, 1, 143, 54, 86, 40, 20, 24, 14, 7, 8, 4, 2, 2, 232, 88, 141, 66, 33, 40, 24, 12, 14, 8, 4, 4, 2, 1, 376, 143, 230, 108, 54, 66
Offset: 0

Views

Author

Kival Ngaokrajang, Mar 14 2015

Keywords

Comments

Refer to A255870, the number of pentagrams on one side of the outer layer (including pentagrams on two vertices) at n iterations would be T(n,0), the next layers k >= 1 T(n,k) are the number of pentagrams toward the center. For k >= 2, the row length is A032766. The first differences of A255870 = 5*(rows sum - 1). T(n,k) = A000071 with a shift for k = 0 or k mod 3 = 1. T(n,2) = A006327 with a shift. For k >= 3, T(n,k) = 2*A000071 with a shift for k mod 3 = 0 or 2. See illustration in the links.

Examples

			Irreuglar triangle begins:
n/k  0  1  2  3  4  5  6  7  8 ...
0   1
1   2
2   4  1
3   7  2  2
4  12  4  5  2  1
5  20  7 10  4  2  2
6  33 12 18  8  4  4  2  1
7  54 20 31 14  7  8  4  2  2
8  88 33 52 24 12 14  8  4  4
...
		

Crossrefs

Programs

  • PARI
    {for(n=0, 20, if(n<2, lk=0, lk=floor(3*(n-2)/2)+1); for (k=0, lk, if(k<>0, if(k<>2, if(Mod(k,3)==1, t=fibonacci(n+1-2*(k-1)/3)-1, t=2*(fibonacci(n+2-ceil((2*k+1)/3))-1)), t=fibonacci(n+2)-3), t=fibonacci(n+3-2*k/3)-1); print1(t, ", ")))}
Showing 1-9 of 9 results.