A258239 Irregular triangle (Beatty tree for r = 2 + sqrt(2)), T, of all nonnegative integers, each exactly once, as determined in Comments.

0, 3, 1, 13, 6, 4, 47, 2, 17, 23, 14, 163, 5, 7, 10, 51, 61, 81, 48, 559, 27, 37, 15, 18, 20, 24, 167, 177, 211, 279, 164, 1911, 8, 11, 54, 64, 71, 85, 95, 129, 49, 52, 62, 82, 563, 573, 607, 723, 955, 560, 6527, 30, 40, 16, 19, 21, 25, 28, 38, 170, 180, 187

Offset: 1

Author

Clark Kimberling, Jun 05 2015

Keywords

• nonn
• tabf
• easy

Comments

Suppose that r is an irrational number > 1, and let s = r/(r-1), so that the sequences u and v defined by u(n) = floor(r*n) and v(n) = floor(s*n), for n >=1 are the Beatty sequences of r and s, and u and v partition the positive integers.

The tree T has root 0 with an edge to 3, and all other edges are determined as follows: if x is in u(v), then there is an edge from x to floor(r + r*x) and an edge from x to ceiling(x/r); otherwise there is an edge from x to floor(r + r*x). (Thus, the only branchpoints are the numbers in u(v).)

Another way to form T is by "backtracking" to the root 0. Let b(x) = floor[x/r] if x is in (u(n)), and b(x) = floor[r*x] if x is in (v(n)). Starting at any vertex x, repeated applications of b eventually reach 0. The number of steps to reach 0 is the number of the generation of T that contains x. (See Example for x = 8).

See A258212 for a guide to Beatty trees for various choices of r.

Examples

			Rows (or generations, or levels) of T:
0
3
1   13
6   4   47
2   23  17  14   163
10  7   81  5    61   51   48   559
37  27  24  279  20   18   211  15   177   167  164   1911
Generations 0 to 7 of the tree are drawn by the Mathematica program.  In T, the path from 0 to 8 is (0,3,1,6,23,7,27,8).  The path obtained by backtracking (i.e., successive applications of the mapping b in Comments) is (8,27,7,23,6,1,3,0).
		

Crossrefs

Cf. A001951, A001952, A258240 (path-length, 0 to n), A258212

Programs

Mathematica

r = 2+Sqrt[2]; k = 1000; w = Map[Floor[r #] &, Range[k]];
f[x_] := f[x] = If[MemberQ[w, x], Floor[x/r], Floor[r*x]];
b := NestWhileList[f, #, ! # == 0 &] &;
bs = Map[Reverse, Table[b[n], {n, 0, k}]];
generations = Table[DeleteDuplicates[Map[#[[n]] &, Select[bs, Length[#] > n - 1 &]]], {n, 8}]
paths = Sort[Map[Reverse[b[#]] &, Last[generations]]]
graph = DeleteDuplicates[Flatten[Map[Thread[Most[#] -> Rest[#]] &, paths]]]
TreePlot[graph, Top, 0, VertexLabeling -> True, ImageSize -> 700]
Map[DeleteDuplicates, Transpose[paths]] (* Peter J. C. Moses,May 21 2015 *)