cp's OEIS Frontend

A258667 A total of n married couples, including a mathematician M and his wife, are to be seated at the 2n chairs around a circular table, with no man seated next to his wife. After the ladies are seated at every other chair, M is the first man allowed to choose one of the remaining chairs. The sequence gives the number of ways of seating the other men, with no man seated next to his wife, if M chooses the chair that is 9 seats clockwise from his wife's chair.

%I A258667 #66 Sep 03 2023 23:40:06
%S A258667 0,0,0,0,0,20,116,791,6205,55004,543596,5922929,70518903,910711188,
%T A258667 12678337924,189252400363,3015217931281,51067619058668,
%U A258667 916176426367084,17355904144230373,346195850528456683,7252654441430368404,159210363452786908116,3654550890657000160319
%N A258667 A total of n married couples, including a mathematician M and his wife, are to be seated at the 2n chairs around a circular table, with no man seated next to his wife. After the ladies are seated at every other chair, M is the first man allowed to choose one of the remaining chairs. The sequence gives the number of ways of seating the other men, with no man seated next to his wife, if M chooses the chair that is 9 seats clockwise from his wife's chair.
%C A258667 This is a variation of the classic ménage problem (cf. A000179).
%C A258667 It is known [Riordan, ch. 8, ex. 7(b)] that, after the ladies are seated at every other chair, the number U_n of ways of seating the men in the ménage problem has asymptotic expansion U_n ~ e^(-2)*n!*(1 + Sum_{k>=1} (-1)^k/(k!(n-1)_k)), where (n)_k = n*(n-1)*...*(n-k+1).
%C A258667 Therefore, it is natural to conjecture that a(n) ~ e^(-2)*n!/(n-2)*(1 + Sum_{k>=1} (-1)^k/(k!(n-1)_k)).
%D A258667 I. Kaplansky and J. Riordan, The problème des ménages, Scripta Math. 12, (1946), 113-124.
%D A258667 J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, chs. 7, 8.
%H A258667 I. Kaplansky and J. Riordan, <a href="/A000166/a000166_1.pdf">The problème des ménages</a>, Scripta Math. 12, (1946), 113-124. [Scan of annotated copy]
%H A258667 Peter J. C. Moses, <a href="/A258667/a258667_1.pdf">Seatings for 6 couples</a>
%H A258667 E. Lucas, <a href="https://archive.org/details/thoriedesnombre00lucagoog/page/n495">Sur le problème des ménages</a>, Théorie des nombres, Paris, 1891, 491-496.
%H A258667 Vladimir Shevelev, Peter J. C. Moses, <a href="http://arxiv.org/abs/1101.5321">The ménage problem with a known mathematician</a>, arXiv:1101.5321 [math.CO], 2011-2015.
%H A258667 Vladimir Shevelev and Peter J. C. Moses, <a href="http://www.emis.de/journals/INTEGERS/papers/q72/q72.Abstract.html">Alice and Bob go to dinner: A variation on menage</a>, INTEGERS, Vol. 16(2016), #A72.
%H A258667 J. Touchard, <a href="http://gallica.bnf.fr/ark:/12148/bpt6k31506/f631.image">Sur un problème de permutations</a>, C.R. Acad. Sci. Paris, 198 (1934), 631-633.
%F A258667 For n <= 5, a(n)=0; otherwise a(n) = Sum_{0<=k<=n-1}(-1)^k*(n-k-1)! Sum_{max(k-n+5, 0)<=j<=min(k,4)} binomial(8-j, j)*binomial(2*n-k+j-10, k-j).
%t A258667 a[n_] := If[n<6, 0, Sum[(-1)^k (n-k-1)! Sum[Binomial[8-j, j] Binomial[2n-k+j-10, k-j], {j, Max[k-n+5, 0], Min[k, 4]}], {k, 0, n-1}]];
%t A258667 Array[a, 24] (* _Jean-François Alcover_, Sep 19 2018 *)
%o A258667 (PARI) a(n) = if (n<=5, 0, sum(k=0, n-1, (-1)^k*(n-k-1)!*sum(j=max(k-n+5, 0), min(k,4), binomial(8-j, j)*binomial(2*n-k+j-10, k-j)))); \\ _Michel Marcus_, Jun 26 2015
%Y A258667 Cf. A000179, A258664, A258665, A258666, A258673, A259212.
%K A258667 nonn
%O A258667 1,6
%A A258667 _Vladimir Shevelev_ and _Peter J. C. Moses_, Jun 07 2015