cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A261462 Least positive integer k such that prime(prime(k)), prime(prime(k*n)), prime(p) and prime(q) form a 4-term arithmetic progression for some pair of primes p and q.

Original entry on oeis.org

1, 5109, 879, 27956, 103840, 32205, 21404, 1800, 4241, 81794, 2355, 4352, 14974, 8552, 26159, 17621, 91986, 52574, 73764, 4699, 12546, 27347, 71148, 6819, 333, 38830, 28809, 2058, 24609, 84, 11478, 226251, 21383, 54, 2930, 36423, 2602, 22, 47668, 15594, 19, 56106, 41913, 72620, 211070, 9022, 2587, 10316, 74965, 26852
Offset: 1

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Author

Zhi-Wei Sun, Aug 20 2015

Keywords

Comments

Conjecture: (i) Any positive rational number r can be written as m/n, where m and n are positive integers such that (prime(prime(m))+prime(prime(n)))/2 = prime(p) for some prime p.
(ii) Any positive rational number r <= 1 can be written as m/n, where m and n are positive integers such that prime(prime(m)),prime(prime(n)), prime(p) and prime(q) form a 4-term arithmetic progression for some pair of primes p and q.
(iii) For any integer k > 2, the set {prime(p): p is prime} contains infinitely many nontrivial k-term arithmetic progressions.

Examples

			a(2) = 5109 since prime(prime(5109)) = 608591, prime(prime(5109*2)) = 1401791, prime(162343) = 2194991, and prime(216023) = 2988191 form a 4-term arithmetic progression with 162343 and 216023 both prime.
		

References

  • Zhi-Wei Sun, Problems on combinatorial properties of primes, in: M. Kaneko, S. Kanemitsu and J. Liu (eds.), Number Theory: Plowing and Starring through High Wave Forms, Proc. 7th China-Japan Seminar (Fukuoka, Oct. 28 - Nov. 1, 2013), Ser. Number Theory Appl., Vol. 11, World Sci., Singapore, 2015, pp. 169-187.

Crossrefs

Programs

  • Mathematica
    f[n_]:=Prime[Prime[n]]
    PQ[p_]:=PrimeQ[p]&&PrimeQ[PrimePi[p]]
    Do[k=0;Label[bb];k=k+1;If[PQ[2*f[k*n]-f[k]]&&PQ[3*f[k*n]-2*f[k]],Goto[aa],Goto[bb]];Label[aa];Print[n," ", k];Continue,{n,1,50}]
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