cp's OEIS Frontend

A261416 Let b(k) denote A260273(k). It appears that for k >= 200, whenever b(k) just passes a power of 2, 2^m say, the successive differences b(k)-2^m converge to this sequence.

%I A261416 #13 Sep 17 2015 20:10:46
%S A261416 2,5,8,11,17,20,23,29,38,43,49,54,61,70,75,81,84,87,93,102,107,114,
%T A261416 119,128,131,136,139,145,148,151,157,167,173,180,187,196,201,206,211,
%U A261416 218,225,230,235,244,253,262,267,273,276,279,285,294,299,305,310,317,327,333,340,343,349,358,365,372,381
%N A261416 Let b(k) denote A260273(k). It appears that for k >= 200, whenever b(k) just passes a power of 2, 2^m say, the successive differences b(k)-2^m converge to this sequence.
%C A261416 It would be nice to have an independent characterization of this sequence.
%C A261416 A partial answer: set a(0)=2, and for n>0, a(n) = A261281(a(n-1)). - _N. J. A. Sloane_, Sep 17 2015
%e A261416 At k=200, b(k)=b(200)=1026 has just passed 2^10. The successive differences b(200+i)-2^10 (i>=0) beyond this point are 2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, [165, ...], which are the first 31 terms of the present sequence.
%e A261416 At k=371, b(371)=2050, and the successive differences b(371+i)-2^11 are 2, 5, ..., 279, 285, ... giving the first 51 terms of the present sequence.
%Y A261416 Cf. A260273, A261281. For when A260273 just passes a power of 2, see A261396.
%K A261416 nonn
%O A261416 0,1
%A A261416 _N. J. A. Sloane_, Aug 25 2015