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A261729 Putative inverse of conjectured permutation in A261725.

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%I A261729 #7 Sep 01 2015 03:41:37
%S A261729 0,1,2,3,4,5,6,7,8,9,19,18,17,16,15,14,13,12,11,10,20,21,22,23,24,25,
%T A261729 26,27,28,29,39,38,37,36,35,34,33,32,31,30,40,41,42,43,44,45,46,47,48,
%U A261729 49,59,58,57,56,55,54,53,52,51,50,60,61,62,63,64,65,66,67
%N A261729 Putative inverse of conjectured permutation in A261725.
%C A261729 a(n) = A003100(n) for n < 100, but a(100) = 109, A003100(100) = 190.
%C A261729 a(n) = A118757(n) for n < 100, but a(100) = 109, A118757(100) = 190.
%C A261729 a(n) = A118758(n) for n < 201, but a(201) = 209, A118758(201) = 211.
%C A261729 a(n) = A174025(n) for n < 100, but a(100) = 109, A174025(100) = 199.
%C A261729 a(n) = A261725(n) for n < 100, but a(100) = 109, A261725(100) = 190.
%H A261729 Paul Tek, <a href="/A261729/b261729.txt">Table of n, a(n) for n = 0..10000</a>
%Y A261729 Cf. A261725.
%K A261729 nonn,base
%O A261729 0,3
%A A261729 _Paul Tek_, Aug 30 2015