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A264009 Table T(i,j) = nonnegative k at which lcm(i+k,j+k) reaches the minimum, read by antidiagonals (i>=1, j>=1).

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 3, 0, 0, 0, 0, 3, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 5, 2, 2, 0, 0, 2, 2, 5, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 4, 1, 1, 0, 0, 1, 1, 4, 1, 0, 0, 0, 1, 2, 3, 0, 0, 0, 3, 2, 1, 0, 0, 0, 9, 0, 3, 0, 0, 0, 0, 0, 0, 3, 0, 9, 0
Offset: 1

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Author

Ivan Neretin, Oct 31 2015

Keywords

Comments

T(i,j) = T(j,i).
T(i,j) <= |i-j|.
If i divides j or vice versa, then T(i,j) = 0.

Examples

			Let i=10, j=3. Then lcm(i,j)=30, lcm(i+1,j+1)=44, lcm(i+2,j+2)=60, lcm(i+3,j+3)=78, and lcm(i+4,j+4)=14, which is the minimum. Hence T(10,3)=T(3,10)=4.
		

Crossrefs

Cf. A003990.