A264059 T(n,k)=Number of (n+1)X(k+1) arrays of permutations of 0..(n+1)*(k+1)-1 with each element having index change +-(.,.) 0,0 1,2 or 2,-2.
1, 2, 1, 4, 8, 1, 8, 64, 18, 1, 16, 216, 324, 45, 1, 32, 729, 2592, 2025, 125, 1, 64, 3375, 20736, 32400, 15625, 320, 1, 128, 15625, 207360, 518400, 450000, 102400, 832, 1, 256, 64000, 2073600, 11151360, 12960000, 5760000, 692224, 2197, 1, 512, 262144
Offset: 1
Examples
Some solutions for n=4 k=4 ..0..1..9.11..4....0..1..9.11..4....0..1.10..3..4....0..8..9..3..4 ..5..6..7.16..2....5..6..7..8..2....5..6.14..8..9....5.13..7..1..2 .17..3.19.21.14...10..3.20.13.22....2.18.12.21..7...10.11.20..6.22 .22..8.10.18.12...15.23.24.18.19...15.16.24.11.19...15.16.24.18.19 .20.13.15.23.24...12.21.14.16.17...20.13.22.23.17...12.21.14.23.17
Links
- R. H. Hardin, Table of n, a(n) for n = 1..97
Crossrefs
Row 1 is A000079(n-1).
Formula
Empirical for column k:
k=1: a(n) = a(n-1)
k=2: a(n) = 3*a(n-1) -a(n-2) +3*a(n-3) -9*a(n-4) +3*a(n-5) -a(n-6) +3*a(n-7) -a(n-8)
k=3: [order 17]
k=4: [order 8] for n>10
k=5: a(n) = 25*a(n-1) for n>3
Empirical for row n:
n=1: a(n) = 2*a(n-1)
n=2: [order 12]
n=3: a(n) = 10*a(n-1) for n>5
n=4: [order 32]
Comments