A269306 a(n+1) is the smallest integer such that the difference between its digital sum and the digital sum of a(n) is n.
0, 1, 3, 6, 19, 69, 399, 1999, 9999, 99999, 1999999, 39999999, 699999999, 19999999999, 699999999999, 39999999999999, 1999999999999999, 99999999999999999, 9999999999999999999, 1999999999999999999999
Offset: 1
Examples
a(8) = 1999 and 1 + 9 + 9 + 9 = 28; so a(9) = 9999 because 9 + 9 + 9 + 9 = 36 and 36 - 28 = 8.
Programs
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PARI
findnext(x, k) = {sx = sumdigits(x); y = 1; while (sumdigits(y) - sx != k, y++); y; } lista(nn) = {print1(x = 0, ", "); for (k=1, nn, y = findnext(x, k); print1(y, ", "); x = y; ); } -
Python
s = 0 for i in range(0, 100): alfa = "" k = i + s s = k while k > 9: alfa = alfa + "9" k = k - 9 alfa = str(k) + alfa print(alfa)
Comments