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A272327 Table read by antidiagonals: T(n, k) is the least i > n such that n divides i^k (n > 0, k > 0).

%I A272327 #12 Apr 28 2016 21:02:19
%S A272327 2,4,2,6,4,2,8,6,4,2,10,6,6,4,2,12,10,6,6,4,2,14,12,10,6,6,4,2,16,14,
%T A272327 12,10,6,6,4,2,18,12,14,12,10,6,6,4,2,20,12,10,14,12,10,6,6,4,2,22,20,
%U A272327 12,10,14,12,10,6,6,4,2,24,22,20,12,10,14,12,10,6
%N A272327 Table read by antidiagonals: T(n, k) is the least i > n such that n divides i^k (n > 0, k > 0).
%C A272327 T(n, k) = 2*n for squarefree n.
%H A272327 Peter Kagey, <a href="/A272327/b272327.txt">Rows n = 1..141</a>, flattened
%e A272327 a(1) = T(1, 1) = 2  because 1 divides 2^1
%e A272327 a(2) = T(2, 1) = 4  because 2 divides 4^1
%e A272327 a(3) = T(1, 2) = 2  because 1 divides 2^2
%e A272327 a(4) = T(3, 1) = 6  because 3 divides 6^1
%e A272327 a(5) = T(2, 2) = 4  because 2 divides 4^2
%e A272327 a(6) = T(1, 3) = 2  because 1 divides 2^3
%e A272327 a(7) = T(4, 1) = 8  because 4 divides 8^1
%e A272327 a(8) = T(3, 2) = 6  because 3 divides 6^2
%e A272327 a(9) = T(2, 3) = 4  because 2 divides 4^3
%e A272327 a(10) = T(1, 4) = 2 because 1 divides 2^4
%e A272327 Triangle begins:
%e A272327    2  2 2 2 2 2
%e A272327    4  4 4 4 4
%e A272327    6  6 6 6
%e A272327    8  6 6
%e A272327   10 10
%e A272327   12
%t A272327 Table[Function[m, SelectFirst[Range[m + 1, 10^3], Divisible[#^k, m] &]][n - k + 1], {n, 12}, {k, n}] // Flatten (* _Michael De Vlieger_, Apr 25 2016, Version 10 *)
%Y A272327 Cf. A254732 (second column), A254733 (third column), A254734 (fourth column), A073353 (main diagonal).
%K A272327 nonn,tabl
%O A272327 1,1
%A A272327 _Peter Kagey_, Apr 25 2016