A273063 Numbers k such that (112*10^k + 17)/3 is prime.
0, 1, 2, 3, 4, 8, 44, 53, 79, 89, 95, 120, 224, 259, 290, 488, 725, 821, 1815, 3096, 3100, 3404, 5909, 8054, 11879, 17298, 25588, 41516, 127324, 191900
Offset: 1
Examples
3 is in this sequence because (112*10^3+17)/3 = 37339 is prime. Initial terms and associated primes: a(1) = 0, 43; a(2) = 1, 379: a(3) = 2, 3739; a(4) = 3, 37339; a(5) = 4, 373339, etc.
Links
- Makoto Kamada, Factorization of near-repdigit-related numbers.
- Makoto Kamada, Search for 373w9.
Programs
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Mathematica
Select[Range[0, 100000], PrimeQ[(112*10^# + 17)/3] &]
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PARI
is(n)=ispseudoprime((112*10^n + 17)/3) \\ Charles R Greathouse IV, Jun 13 2017
Extensions
a(29)-a(30) from Robert Price, Mar 05 2020
Comments