A276040 Least k such that n^n divides phi(k^k) (k > 0).
1, 4, 6, 8, 10, 12, 14, 12, 18, 20, 22, 24, 26, 28, 30, 24, 34, 36, 38, 40, 42, 44, 46, 36, 50, 52, 45, 56, 58, 60, 62, 48, 66, 68, 70, 72, 74, 76, 78, 60, 82, 84, 86, 88, 90, 92, 94, 72, 98, 100, 102, 104, 106, 90, 110, 84, 114, 116, 118, 120
Offset: 1
Keywords
Examples
a(3) = 6 because 3^3 divides phi(6^6) = 15552.
Crossrefs
Cf. A064447.
Programs
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Mathematica
Table[k = 1; While[! Divisible[EulerPhi[k^k], n^n], k++]; k, {n, 60}] (* Michael De Vlieger, Aug 21 2016 *)
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PARI
a(n) = {my(k = 1); while(eulerphi(k^k) % n^n, k++); k; }
Comments