This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A276819 #26 Dec 26 2022 09:47:58 %S A276819 1,5,18,40,71,111,160,218,285,361,446,540,643,755,876,1006,1145,1293, %T A276819 1450,1616,1791,1975,2168,2370,2581,2801,3030,3268,3515,3771,4036, %U A276819 4310,4593,4885,5186,5496,5815,6143,6480,6826,7181,7545,7918,8300,8691,9091,9500,9918,10345,10781,11226,11680,12143,12615 %N A276819 a(n) = (9*n^2 - n)/2 + 1. %C A276819 Diagonal of triangular spiral in A051682. The other 5 diagonals are given by A140064, A117625, A081267, A064225, A006137. See the link as well. %C A276819 First differences are given by A017209. %C A276819 72*a(n) - 71 is a perfect square. - _Klaus Purath_, Jan 14 2022 %H A276819 Colin Barker, <a href="/A276819/b276819.txt">Table of n, a(n) for n = 0..1000</a> %H A276819 Yuriy Sibirmovsky, <a href="/A276819/a276819.png">Six diagonals of the triangular spiral</a>. %H A276819 <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1). %F A276819 a(n) = (9*n^2 - n)/2 + 1. %F A276819 a(n) = a(n-1) + 9*n - 5 with a(0) = 1. %F A276819 From _Colin Barker_, Sep 18 2016: (Start) %F A276819 a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n > 2. %F A276819 G.f.: (1 + 2*x + 6*x^2)/(1 - x)^3. (End) %F A276819 From _Klaus Purath_, Jan 14 2022: (Start) %F A276819 a(n) = A006137(n) - n. %F A276819 A003215(a(n)) - A003215(a(n)-3) = A002378(9*n-1). (End) %F A276819 E.g.f.: exp(x)*(2 + 8*x + 9*x^2)/2. - _Stefano Spezia_, Dec 25 2022 %t A276819 Table[(9*n^2-n)/2+1, {n,0,100}] %o A276819 (PARI) Vec((1+2*x+6*x^2)/(1-x)^3 + O(x^60)) \\ _Colin Barker_, Sep 18 2016 %o A276819 (PARI) a(n) = (9*n^2 - n)/2 + 1; \\ _Altug Alkan_, Sep 18 2016 %Y A276819 Cf. A002378, A003215, A006137, A017209, A051682, A064225, A081267, A117625, A140064. %K A276819 nonn,easy %O A276819 0,2 %A A276819 _Yuriy Sibirmovsky_, Sep 18 2016