A279076 Maximum starting value of X such that repeated replacement of X with X-ceiling(X/6) requires n steps to reach 0.
0, 1, 2, 3, 4, 5, 7, 9, 11, 14, 17, 21, 26, 32, 39, 47, 57, 69, 83, 100, 121, 146, 176, 212, 255, 307, 369, 443, 532, 639, 767, 921, 1106, 1328, 1594, 1913, 2296, 2756, 3308, 3970, 4765, 5719, 6863, 8236, 9884, 11861, 14234, 17081, 20498, 24598, 29518, 35422
Offset: 0
Keywords
Examples
7 -> 7-ceiling(7/6) = 5, 5 -> 5-ceiling(5/6) = 4, 4 -> 4-ceiling(4/6) = 3, 3 -> 3-ceiling(3/6) = 2, 2 -> 2-ceiling(2/6) = 1, 1 -> 1-ceiling(1/6) = 0, so reaching 0 from 7 requires 6 steps; 8 -> 8-ceiling(8/6) = 6, 6 -> 6-ceiling(6/6) = 5, 5 -> 5-ceiling(5/6) = 4, 4 -> 4-ceiling(4/6) = 3, 3 -> 3-ceiling(3/6) = 2, 2 -> 2-ceiling(2/6) = 1, 1 -> 1-ceiling(1/6) = 0, so reaching 0 from 8 (or more) requires 7 (or more) steps; thus, 7 is the largest starting value from which 0 can be reached in 6 steps, so a(6) = 7.
Links
Crossrefs
Cf. A278586.
See the following sequences for maximum starting value of X such that repeated replacement of X with X-ceiling(X/k) requires n steps to reach 0: A000225 (k=2), A006999 (k=3), A155167 (k=4, apparently; see Formula entry there), A279075 (k=5), (this sequence) (k=6), A279077 (k=7), A279078 (k=8), A279079 (k=9), A279080 (k=10). For each of these values of k, is the sequence the L-sieve transform of {k-1, 2k-1, 3k-1, ...}?
Programs
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Magma
a:=[0]; aCurr:=0; for n in [1..51] do aCurr:=Floor(aCurr*6/5)+1; a[#a+1]:=aCurr; end for; a;
Formula
a(n) = floor(a(n-1)*6/5) + 1.
Comments