A280926 Least k such that the first n digits of the decimal expansion of the ratio of the perimeter of a regular k-gon to its diameter match those of Pi.
5, 7, 29, 47, 119, 699, 1407, 4911, 18971, 46803, 119951, 363209, 1276197, 3722389, 19973297, 73605289, 183273481, 390720475, 1671075265, 4541314567, 22107473795, 44810965685, 172567099183, 617945607281, 1835952288687, 3938674815741, 19847928172101
Offset: 1
Examples
An equilateral triangle (k=3) has no diagonals, and a square (k=4) has perimeter/diameter = sqrt(8) = 2.828427..., but a regular pentagon (k=5) has perimeter/diameter = (5/2)*(sqrt(5) - 1) = 3.090169..., whose first digit (3) matches that of Pi = 3.141592..., so a(1)=5. - _Jon E. Schoenfield_, Mar 31 2021 This ratio for a regular 7-gon (heptagon) is 3.115293... (A280533), where 3.1 equals the first two digits of Pi's decimal expansion. Because the first two digits are not 3.1 for k < 7, a(2) = 7.
Formula
a(n) = 1 + 2*floor((1/2)*(1 + sqrt((Pi^3/24)/(Pi-floor(Pi*10^(n-1))/10^(n-1))))). - Jon E. Schoenfield, Mar 28 2021
Extensions
a(13)-a(27) from Jon E. Schoenfield, Mar 28 2021
Comments