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A281005 Numbers n having at least one odd divisor greater than sqrt(2*n).

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%I A281005 #56 Sep 08 2022 08:46:18
%S A281005 3,5,7,9,10,11,13,14,15,17,18,19,21,22,23,25,26,27,29,30,31,33,34,35,
%T A281005 36,37,38,39,41,42,43,44,45,46,47,49,50,51,52,53,54,55,57,58,59,60,61,
%U A281005 62,63,65,66,67,68,69,70,71,73,74,75,76,77,78,79,81,82,83,84,85,86,87,89,90,91,92,93,94,95,97,98,99,100,101,102,103,105
%N A281005 Numbers n having at least one odd divisor greater than sqrt(2*n).
%C A281005 Conjecture 1: also numbers n such that the symmetric representation of sigma(n) has at least one pair of equidistant subparts.
%C A281005 Conjecture 2: the number of pairs of equidistant subparts in the symmetric representation of sigma(k) equals the number of odd divisors of k greater than sqrt(2*k), with k >= 1.
%C A281005 For more information about the subparts see A279387.
%H A281005 Indranil Ghosh, <a href="/A281005/b281005.txt">Table of n, a(n) for n = 1..1000</a>
%e A281005 18 is in the sequence because one of its odd divisors is 9, and 9 is greater than 6, the square root of 2*18.
%e A281005 On the other hand the symmetric representation of sigma(18) has only one part of size 39, which is formed by a central subpart of size 35 and a pair of equidistant subparts [2, 2]. Since there is at least one pair of equidistant subparts, so 18 is in the sequence.
%e A281005 From _Omar E. Pol_, Dec 18 2020: (Start)
%e A281005 The 17th row of triangle A237593 is [9, 4, 2, 1, 1, 1, 1, 2, 4, 9] and the 18th row of the same triangle is [10, 3, 2, 2, 1, 1, 2, 2, 3, 10], so the diagram of the symmetric representation of sigma(18) = 39 is constructed as shown below in figure 1:
%e A281005 .                                     _                                      _
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%e A281005 .                            |    _ _ _|                            |  _ _ _ _|
%e A281005 .                           _|   |                                 _| | |
%e A281005 .                         _|  _ _|                               _|  _|_|
%e A281005 .                     _ _|  _|                               _ _|  _|    2
%e A281005 .                    |     |  39                            |  _ _|
%e A281005 .                    |  _ _|                                | |_ _|
%e A281005 .                    | |                                    | |    2
%e A281005 .   _ _ _ _ _ _ _ _ _| |                   _ _ _ _ _ _ _ _ _| |
%e A281005 .  |_ _ _ _ _ _ _ _ _ _|                  |_ _ _ _ _ _ _ _ _ _|
%e A281005 .                                                              35
%e A281005 .
%e A281005 .   Figure 1. The symmetric               Figure 2. After the dissection
%e A281005 .   representation of sigma(18)           of the symmetric representation
%e A281005 .   has one part of size 39.              of sigma(18) into layers of
%e A281005 .                                         width 1 we can see three subparts.
%e A281005 .                                         The first layer has one subpart of
%e A281005 .                                         size 35. The second layer has
%e A281005 .                                         two equidistant subparts of size 2,
%e A281005 .                                         so 18 is in the sequence.
%e A281005 (End)
%t A281005 Select[Range@ 120, Count[Divisors@ #, d_ /; And[OddQ@ d, d > Sqrt[2 #]]] > 0 &] (* _Michael De Vlieger_, Feb 07 2017 *)
%o A281005 (PARI) isok(n) = my(s=sqrt(2*n)); sumdiv(n, d, (d % 2) && (d > s)) > 0; \\ _Michel Marcus_, Jan 15 2020
%o A281005 (Magma) [k:k in [1..110] | not forall{d:d in Divisors(k)| IsEven(d) or d le Sqrt(2*k)}]; // _Marius A. Burtea_, Jan 15 2020
%Y A281005 Complement of A082662.
%Y A281005 Indices of positive terms in A131576.
%Y A281005 Cf. A000203, A001227, A067742, A071561, A196020, A235791, A236104, A237048, A237270, A237271, A237571, A237593, A244050, A245092, A249351, A262626, A279387, A280850, A280851, A296508.
%K A281005 nonn
%O A281005 1,1
%A A281005 _Omar E. Pol_, Feb 06 2017