A282427 Numbers k such that A282442(k) = ceiling(k/2) + 1.

1, 3, 7, 39, 47, 111, 959, 3319, 7407, 11967, 13007, 16239

Offset: 1

Author

Peter Kagey, Feb 15 2017

Keywords

• nonn
• more

Comments

All terms are odd.

Proof: if A282442(2m) = m + 1, then the step of length m would have to have concluded on exactly the middle step, but a phase with step-length m cannot end on the middle step because the distance from the middle step to the top/bottom of the staircase is equal to m.

Links

• Mathematics Stack Exchange user Sheljohn, A curious sequence.

Crossrefs

Cf. A282442.