This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A283833 #18 Dec 09 2017 11:09:54 %S A283833 1,1,1,3,3,3,2,1,7,7,7,6,5,4,3,2,1,15,15,15,14,13,12,11,10,9,8,7,6,5, %T A283833 4,3,2,1,31,31,31,30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14, %U A283833 13,12,11,10,9,8,7,6,5,4,3,2,1,63,63,63,62,61,60,59,58,57,56,55,54,53,52 %N A283833 For t >= 0, if 2^t + t - 3 <= n <= 2^t + t - 1 then a(n) = 2^t - 1, while if 2^t + t - 1 < n < 2^(t+1) + t - 3 then a(n) = 2^(t+1) + t - 2 - n. %H A283833 Michel Marcus, <a href="/A283833/b283833.txt">Table of n, a(n) for n = 0..4104</a> %H A283833 J.-P. Allouche, J. Shallit, <a href="http://arxiv.org/abs/1605.02361">On the subword complexity of the fixed point of a -> aab, b -> b, and generalizations</a>, arXiv preprint arXiv:1605.02361 [math.CO], 2016. See Table 3. %e A283833 1,1,1; %e A283833 ; %e A283833 3,3,3; %e A283833 2,1; %e A283833 7,7,7; %e A283833 6,5,4,3,2,1; %e A283833 15,15,15; %e A283833 14,13,12,11,10,9,8,7,6,5,4,3,2,1; %e A283833 31,31,31; %e A283833 30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,10,9,8,7,6,5,4,3,2,1; %e A283833 63,63,63; %e A283833 62,61,60,59,... %p A283833 A283833 := proc(n) %p A283833 local t; %p A283833 if n =0 then %p A283833 return 1; %p A283833 end if; %p A283833 for t from 0 do %p A283833 if 2^t+t-3 <= n and n<= 2^t+t-1 then %p A283833 return 2^t-1 ; %p A283833 elif 2^t+t-1 <= n and n<= 2^(t+1)+t-3 then %p A283833 return 2^(t+1)+t-2-n ; %p A283833 end if; %p A283833 end do: %p A283833 end proc: # _R. J. Mathar_, Mar 28 2017 %t A283833 a[0] = 1; a[n_] := For[t = 0, True, t++, Which[2^t + t - 3 <= n && n <= 2^t + t - 1, Return[2^t - 1], 2^t + t - 1 <= n && n <= 2^(t + 1) + t - 3, Return[ 2^(t + 1) + t - 2 - n]]]; %t A283833 Table[a[n], {n, 0, 80}] (* _Jean-François Alcover_, Dec 09 2017, from Maple *) %o A283833 (PARI) a(n) = {if (n==0, return (1)); for (t=0, oo, if (((2^t+t-3) <= n) && (n <= 2^t+t-1), return (2^t-1)); if (((2^t+t-1) <= n) && (n <= 2^(t+1)+t-3), return (2^(t+1)+t-2-n)););} \\ _Michel Marcus_, Aug 21 2017 %Y A283833 Cf. A145071. %K A283833 nonn %O A283833 0,4 %A A283833 _N. J. A. Sloane_, Mar 24 2017