cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A285182 L = A132468(n) = A048669(n)-1 is the length of the longest run of consecutive numbers that have a common factor with n; a(n) = smallest k >= 0 which starts such a run.

Original entry on oeis.org

0, 0, 0, 0, 2, 0, 0, 0, 4, 0, 2, 0, 6, 5, 0, 0, 2, 0, 4, 6, 10, 0, 2, 0, 12, 0, 6, 0, 2, 0, 0, 11, 16, 14, 2, 0, 18, 12, 4, 0, 6, 0, 10, 5, 22, 0, 2, 0, 4, 17, 12, 0, 2, 10, 6, 18, 28, 0, 2, 0, 30, 6, 0, 25, 8, 0, 16, 23, 4, 0, 2, 0, 36, 5, 18, 21, 12, 0, 4, 0, 40, 0, 6, 34, 42, 29, 10, 0, 2, 13, 22, 30
Offset: 2

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Author

N. J. A. Sloane, Apr 19 2017

Keywords

Comments

Related to the Jacobsthal function A048669.
a(n) depends only on the radical A007947(n).

Examples

			If n = 6, among the numbers k = 0,1,2,3,4,5,6,7,... there is a run of L = 3 consecutive numbers, 2,3,4, all with gcd(k,6)>1, starting at k=2, so a(6) = 2.
If n is a prime (or prime power), a(n)=0.
		

Crossrefs

Programs

  • Maple
    acf:=[]; wcf:=[];
    for n from 2 to 120 do
    s:=[seq(j,j=0..4*n)];
    rec:=0;
       for st from 0 to n do
       len:=0;
          for i from 1 to n while gcd(s[st+i],n)>1 do len:=len+1; od:
          if len>rec then rec:=len; w:=st; fi;
       od:
    acf:=[op(acf),rec];
    wcf:=[op(wcf),w];
    od:
    acf; # A132468
    wcf; # A285182