A286261 Numbers whose binary expansion is not a cubefree string.
7, 8, 14, 15, 16, 17, 23, 24, 28, 29, 30, 31, 32, 33, 34, 35, 39, 40, 42, 46, 47, 48, 49, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 78, 79, 80, 81, 84, 85, 87, 88, 92, 93, 94, 95, 96, 97, 98, 99, 103, 104, 106, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130
Offset: 1
Examples
7 is in the sequence, because 7 = 111[2] contains three consecutive "1"s. 8 is in the sequence, because 8 = 1000[2] contains three consecutive "0"s. 42 is in the sequence, because 42 = 101010[2] contains three consecutive "10"s. From the comment follows that all numbers of the form 7*2^k, 8*2^k or 42*2^k are in the sequence, for any k >= 0. All numbers congruent to 7 or congruent to 0 (mod 8) are in the sequence. All numbers of the form m*2^(k+3) +- n with n < 2^k are in the sequence.
Links
- Chai Wah Wu, Table of n, a(n) for n = 1..10000
Programs
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Python
from _future_ import division def is_cubefree(s): l = len(s) for i in range(l-2): for j in range(1,(l-i)//3+1): if s[i:i+2*j] == s[i+j:i+3*j]: return False return True A286261_list = [n for n in range(10**4) if not is_cubefree(bin(n)[2:])] # Chai Wah Wu, May 06 2017
Formula
a(n) ~ n: the sequence has asymptotic density one.
Comments