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A288938 Positions of 1 in A288936; complement of A288937.

%I A288938 #4 Jun 28 2017 22:25:38
%S A288938 3,6,7,9,10,12,13,14,16,17,18,19,21,22,23,24,25,27,28,29,30,31,32,34,
%T A288938 35,36,37,38,39,40,42,43,44,45,46,47,48,49,51,52,53,54,55,56,57,58,59,
%U A288938 61,62,63,64,65,66,67,68,69,70,72,73,74,75,76,77,78,79,80
%N A288938 Positions of 1 in A288936; complement of A288937.
%C A288938 a(n)/n -> 1.
%H A288938 Clark Kimberling, <a href="/A288938/b288938.txt">Table of n, a(n) for n = 1..10000</a>
%t A288938 z = 11; (* number of iterates *)
%t A288938 s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];
%t A288938 w[n_] := StringReplace[w[n - 1], {"00" -> "0010", "01" -> "011", "10" -> "011"}]
%t A288938 TableForm[Table[w[n], {n, 0, 10}]]
%t A288938 st = ToCharacterCode[w[z]] - 48   (* A288936 *)
%t A288938 Flatten[Position[st, 0]]  (* A288937 *)
%t A288938 Flatten[Position[st, 1]]  (* A288938 *)
%Y A288938 Cf. A288936, A288937.
%K A288938 nonn,easy
%O A288938 1,1
%A A288938 _Clark Kimberling_, Jun 28 2017