A290131 Number of regions in a regular drawing of the complete bipartite graph K_{n,n}.

0, 2, 12, 40, 96, 204, 368, 634, 1012, 1544, 2236, 3186, 4360, 5898, 7764, 10022, 12712, 16026, 19844, 24448, 29708, 35756, 42604, 50602, 59496, 69650, 80940, 93600, 107540, 123316, 140428, 159642, 180632, 203618, 228556, 255822, 285080, 317326, 352020, 389498

Offset: 1

Author

R. J. Mathar, Jul 20 2017

Keywords

• nonn
• easy

Links

• Chai Wah Wu, Table of n, a(n) for n = 1..10000
• Martin Griffiths, Counting the regions in a regular drawing of K_{n,n}, J. Int. Seq. 13 (2010) # 10.8.5. See Lemma 2 and Table 1.
• Stéphane Legendre, The Number of Crossings in a Regular Drawing of the Complete Bipartite Graph, J. Integer Seqs., Vol. 12, 2009.
• N. J. A. Sloane, Families of Essentially Identical Sequences, Mar 24 2021 (Includes this sequence)
• Eric Weisstein's World of Mathematics, Complete Bipartite Graph

Crossrefs

Cf. A115004, A159065, A290132, A331754.

For K_n see A007569, A007678, A135563.

The following eight sequences are all essentially the same. The simplest is A115004(n), which we denote by z(n). Then A088658(n) = 4*z(n-1); A114043(n) = 2*z(n-1)+2*n^2-2*n+1; A114146(n) = 2*A114043(n); A115005(n) = z(n-1)+n*(n-1); A141255(n) = 2*z(n-1)+2*n*(n-1); A290131(n) = z(n-1)+(n-1)^2; A306302(n) = z(n)+n^2+2*n. - N. J. A. Sloane, Feb 04 2020

Programs

Maple

A290131 := proc(n)
    A115004(n-1)+(n-1)^2 ;
end proc:
seq(A290131(n),n=1..30) ;

Mathematica

z[n_] := Sum[(n - i + 1)(n - j + 1) Boole[GCD[i, j] == 1], {i, n}, {j, n}];
a[n_] := z[n - 1] + (n - 1)^2;
Array[a, 40] (* Jean-François Alcover, Mar 24 2020 *)

Python

from math import gcd
def a115004(n):
    r=0
    for a in range(1, n + 1):
        for b in range(1, n + 1):
            if gcd(a, b)==1:r+=(n + 1 - a)*(n + 1 - b)
    return r
def a(n): return a115004(n - 1) + (n - 1)**2
print([a(n) for n in range(1, 51)]) # Indranil Ghosh, Jul 20 2017, after Maple code

Python

from sympy import totient
def A290131(n): return 2*(n-1)**2 + sum(totient(i)*(n-i)*(2*n-i) for i in range(2,n)) # Chai Wah Wu, Aug 16 2021

Formula

a(n) = A115004(n-1) + (n-1)^2.

a(n) = 2*(n-1)^2 + Sum_{i=2..n-1} (n-i)*(2n-i)*phi(i). - Chai Wah Wu, Aug 16 2021