A292956 Rectangular array by antidiagonals: T(n,m) = rank of n*(r+m) when all the numbers k*(r+h), where r = sqrt(2), k>=1, h>=0, are jointly ranked.
1, 2, 3, 4, 7, 5, 6, 11, 13, 9, 8, 17, 21, 19, 12, 10, 23, 30, 32, 26, 16, 14, 29, 39, 46, 44, 35, 20, 15, 36, 50, 59, 61, 55, 42, 24, 18, 41, 62, 75, 81, 77, 67, 51, 28, 22, 49, 72, 90, 100, 102, 95, 82, 60, 33, 25, 56, 84, 106, 120, 128, 125, 113, 93, 69
Offset: 1
Examples
Northwest corner: 1 2 4 6 8 10 14 15 18 3 7 11 17 23 29 36 41 49 5 13 21 30 39 50 62 72 84 9 19 32 46 59 75 90 106 124 12 26 44 61 81 100 120 142 165 The numbers k*(r+h), approximately: (for k=1): 1.414 2.414 3.414 ... (for k=2): 2.828 4.828 6.828 ... (for k=3): 4.242 7.242 10.242 ... Replacing each by its rank gives 1 2 4 3 7 11 5 13 21
Links
- Clark Kimberling, Antidiagonals n=1..60, flattened
Crossrefs
Cf. A182846.
Programs
Formula
T(n,m) = Sum_{k=1...[n + m*n/r]} [1 - r + n*(r + m)/k], where r=sqrt(2) and [ ]=floor.
Comments