A292960 Rectangular array by antidiagonals: T(n,m) = rank of n*(r+m) when all the numbers k*(r+h), where r = ((1+sqrt(5))/2)^2, k>=1, h>=0, are jointly ranked.
1, 2, 4, 3, 7, 9, 5, 11, 15, 13, 6, 16, 22, 23, 19, 8, 20, 29, 34, 32, 27, 10, 25, 38, 44, 47, 43, 33, 12, 30, 46, 57, 62, 61, 53, 40, 14, 36, 55, 69, 78, 81, 75, 66, 49, 17, 41, 65, 83, 95, 102, 100, 91, 76, 56, 18, 48, 74, 96, 112, 122, 124, 119, 107, 88
Offset: 1
Examples
Northwest corner: 1 2 3 5 6 8 10 4 7 11 16 20 25 30 9 15 22 29 38 46 55 13 23 34 44 57 69 83 19 32 47 62 78 95 112 27 43 61 81 102 122 145 The numbers k*(r+h), approximately: (for k=1): 2.618 3.618 4.618 ... (for k=2): 5.236 7.236 9.236 ... (for k=3): 7.854 10.854 13.854 ... Replacing each k*(r+h) by its rank gives 1 2 3 4 7 11 9 15 22
Links
- Clark Kimberling, Antidiagonals n=1..60, flattened
Programs
Formula
T(n,m) = Sum_{k=1...[n + m*n/r]} [1 - r + n*(r + m)/k], where r=(GoldenRatio)^2 and [ ]=floor.
Comments