A293054 Rectangular array by antidiagonals: T(n,m) = rank of n*sqrt(5)+m when all the numbers k*sqrt(5)+h, for k >= 1, h >= 0, are jointly ranked.
1, 2, 4, 3, 6, 9, 5, 8, 12, 16, 7, 11, 15, 20, 25, 10, 14, 19, 24, 30, 37, 13, 18, 23, 29, 35, 43, 51, 17, 22, 28, 34, 41, 49, 58, 67, 21, 27, 33, 40, 47, 56, 65, 75, 85, 26, 32, 39, 46, 54, 63, 73, 83, 94, 106, 31, 38, 45, 53, 61, 71, 81, 92, 103, 116, 129
Offset: 1
Examples
Northwest corner: 1 2 3 5 7 10 13 4 6 8 11 14 18 22 9 12 15 19 23 28 33 16 20 24 29 34 40 46 25 30 35 41 47 54 61 37 43 49 56 63 71 79 51 58 65 73 81 90 99 67 75 83 92 101 111 121 85 94 103 113 123 134 145 The numbers k*r+h, approximately: (for k=1): 2.236 3.236 3.236 ... (for k=2): 4.472 5.472 6.472 ... (for k=3): 6.708 7.708 8.708 ... Replacing each k*r+h by its rank gives 1 2 3 4 6 8 9 12 15
Links
- Clark Kimberling, Antidiagonals n=1..60, flattened
Crossrefs
Cf. A283962.
Programs
Formula
T(n,m) = Sum_{k=1...n + [m/r]} m+1+[(n-k)r], where r = sqrt(5), [ ]=floor.
Comments