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A293406 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + 1, where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4.

%I A293406 #7 Nov 02 2017 09:20:16
%S A293406 1,3,9,18,34,60,103,174,289,476,779,1270,2065,3352,5435,8807,14263,
%T A293406 23092,37378,60494,97897,158417,256341,414786,671156,1085972,1757159,
%U A293406 2843163,4600355,7443552,12043943,19487532,31531513,51019084,82550637,133569762
%N A293406 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + 1, where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4.
%C A293406 The complementary sequences a() and b() are uniquely determined by the titular equation and initial values. The initial values of each sequence in the following guide are a(0) = 1, a(2) = 3, b(0) = 2, b(1) = 4:
%C A293406 Conjecture: a(n)/a(n-1) -> (1 + sqrt(5))/2, the golden ratio.  See A293358 for a guide to related sequences.
%H A293406 Clark Kimberling, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL10/Kimberling/kimberling26.pdf">Complementary equations</a>, J. Int. Seq. 19 (2007), 1-13.
%e A293406 a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4, so that
%e A293406 a(2) = a(1) + a(0) + b(1) + 1 = 8;
%e A293406 Complement: (b(n)) = (2, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 15, 17, ...)
%t A293406 mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
%t A293406 a[0] = 1; a[1] = 3; b[0] = 2; b[1] = 4;
%t A293406 a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1] + 1;
%t A293406 b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
%t A293406 Table[a[n], {n, 0, 40}]  (* A293406 *)
%t A293406 Table[b[n], {n, 0, 10}]
%Y A293406 Cf. A001622 (golden ratio), A293076.
%K A293406 nonn,easy
%O A293406 0,2
%A A293406 _Clark Kimberling_, Oct 29 2017