A294543 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + 2, where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
1, 2, 9, 18, 35, 62, 107, 181, 301, 496, 812, 1324, 2153, 3495, 5667, 9183, 14872, 24078, 38974, 63077, 102077, 165181, 267286, 432496, 699812, 1132339, 1832183, 2964555, 4796772, 7761362, 12558170, 20319570, 32877779, 53197389, 86075209, 139272640
Offset: 0
Examples
a(0) = 1, a(1) = 2, b(0) = 3, so that b(1) = 4 (least "new number"); a(2) = a(1) + a(0) + b(1) + 2 = 9. Complement: (b(n)) = (3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, ...).
Links
- Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13.
Programs
-
Mathematica
mex := First[Complement[Range[1, Max[#1] + 1], #1]] &; a[0] = 1; a[1] = 3; b[0] = 2; a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1] + 2; b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]]; Table[a[n], {n, 0, 40}] (* A294543 *) Table[b[n], {n, 0, 10}]
Comments