A294547 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + 2n, where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
1, 2, 11, 24, 49, 90, 159, 272, 457, 759, 1249, 2044, 3332, 5418, 8795, 14261, 23107, 37422, 60586, 98068, 158717, 256852, 415639, 672564, 1088279, 1760922, 2849283, 4610290, 7459661, 12070042, 19529797, 31599936, 51129833, 82729872, 133859811, 216589792
Offset: 0
Examples
a(0) = 1, a(1) = 2, b(0) = 3, so that b(1) = 4 (least "new number"); a(2) = a(1) + a(0) + b(1) + 4 = 11. Complement: (b(n)) = (3, 4, 5, 6, 7, 8, 9, 10, 12, 13, 14, 15, 16, ...).
Links
- Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13.
Programs
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Mathematica
mex := First[Complement[Range[1, Max[#1] + 1], #1]] &; a[0] = 1; a[1] = 3; b[0] = 2; a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1] + 2n; b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]]; Table[a[n], {n, 0, 40}] (* A294547 *) Table[b[n], {n, 0, 10}]
Comments