A294861 Solution of the complementary equation a(n) = a(n-2) + b(n-2) + 1, where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
1, 2, 5, 7, 12, 16, 22, 27, 34, 41, 49, 57, 67, 76, 87, 97, 109, 121, 134, 147, 161, 176, 191, 207, 223, 240, 257, 276, 294, 314, 333, 354, 374, 397, 418, 442, 464, 489, 512, 538, 563, 590, 616, 644, 671, 700, 728, 759, 788, 820, 850, 883, 914, 948, 980
Offset: 0
Examples
a(0) = 1, a(1) = 2, b(0) = 3 b(1) = 4 (least "new number") a(2) = a(0) + b(0) + 1 = 5 Complement: (b(n)) = (3, 4, 6, 8, 9, 10, 11, 12, 14, 15, 17, ...)
Links
- Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13.
Programs
-
Mathematica
mex := First[Complement[Range[1, Max[#1] + 1], #1]] &; a[0] = 1; a[1] = 2; b[0] = 3; a[n_] := a[n] = a[n - 2] + b[n - 2] + 1; b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]]; Table[a[n], {n, 0, 18}] (* A294861 *) Table[b[n], {n, 0, 10}]
Comments