A295196 Numbers n > 1 such that 2^(n-1) and (2*n-m)*2^(((n-1)/2) - floor(log_2(n))) are congruent to 1 (mod n) for at least one of m = 3, m = 7 and m = 15.
7, 23, 31, 47, 71, 79, 263, 271, 1031, 1039, 2063, 4111, 32783, 65543, 65551, 262151, 1048583, 4194319, 8388623, 67108879, 268435463, 1073741831, 1073741839, 4294967311
Offset: 1
Links
- Jonas Kaiser, On the relationship between the Collatz conjecture and Mersenne prime numbers, arXiv:1608.00862 [math.GM], 2016.
Programs
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Mathematica
twoDistableQ[n_] := MemberQ[Mod[(2n - {3, 7, 15}) PowerMod[2, (n - 1)/2 - Floor@ Log2@ n, n], n], 1]; p = 3; twoDistablesList = {}; While[p < 1000000000, If[twoDistableQ@ p, AppendTo[ twoDistablesList, p]]; p = NextPrime@ p]; twoDistablesList (* Robert G. Wilson v, Nov 17 2017 *)
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PARI
a(n) = (n%2) && lift((Mod(2, n)^(n-1))==1) && (lift((Mod((2*n-3), n)*Mod(2, n)^(((n-1)/2)-floor(log(n)/log(2)))) == 1)||lift((Mod((2*n-7), n)*Mod(2, n)^(((n-1)/2)-floor(log(n)/log(2)))) == 1)||lift((Mod((2*n-15), n)*Mod(2, n)^(((n-1)/2)-floor(log(n)/log(2)))) == 1))
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PARI
is(n)=if(Mod(2,n)^(n-1)!=1, return(0)); my(m=Mod(2,n)^(n\2-logint(n,2))); ((2*n-3)*m==1 || (2*n-7)*m==1 || (2*n-15)*m==1) && n>1 \\ Charles R Greathouse IV, Nov 17 2017
Extensions
a(17)-a(24) from Charles R Greathouse IV, Nov 17 2017
Comments