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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A295339 Least k for the inner Theodorus spiral to complete n revolutions.

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%I A295339 #14 Dec 18 2017 04:31:58
%S A295339 15,52,108,184,279,394,530,684,859,1053,1267,1501,1755,2028,2321,2634,
%T A295339 2966,3318,3690,4082,4493,4925,5375,5846,6336,6847,7376,7926,8495,
%U A295339 9085,9693,10322,10970,11638,12326,13034,13761,14508,15275
%N A295339 Least k for the inner Theodorus spiral to complete n revolutions.
%C A295339 Here the points of the inner discrete Theodurus spiral in the complex plane are zhat(k) = rho(k)*exp(i*phihat(k)) with rho(k) = sqrt(k) and phihat(k) starts with phihat(1) = Pi/2 and is not restricted to be <= 2*Pi, it is phihat(k) = Sum_{j=0..k-1} (2*alpha(j+1) - alpha(j)) with alpha(j) = arctan(1/sqrt(j)), for k >= 1. The formula is phihat(k) = phi(k) + alpha(k), with the recurrence for the arguments of the outer spiral phi(k) = phi(k-1) + alpha(k-1), k >= 2, with phi(1) = 0.
%C A295339 If one considers punctured sheets S_n = rho*exp(i*phi_n), with rho > 0 and 2*Pi*(n-1) <= phi_n < 2*Pi*n, for n >= 1, then on sheet S_n there are a(n) - a(n-1) = A296179(n) points zhat, where a(0) = 0.
%C A295339 An analytic continuation of Davis's interpolation of the outer spiral is given in the Waldvogel link (see Figure 2 there). The point zhat(k) (called G_k on Figure 1 there) on the inner spiral is obtained from mirroring the point z(k) (called F_k there) of the outer spiral on the hypotenuse O,z(k+1), for k >= 1. In the present case the arguments phihat(k) of zhat(k) are taken positive.
%C A295339 Conjecture: a(n) = A072895(n) - 2, n >= 1. This follows from the conjecture that the sequences K := {floor(phi(k)/(2*Pi)}_{k >= 1} with phi given above, and Khat:= {floor(phihat(k)/(2*Pi)}_{k >= 1} with phihat given above satisfy Khat(k-2) = K(k), for k >= 3. Note that phihat(k-2) - phi(k) = alpha(k-2) - alpha(k-1) =: delta(k) = arctan((sqrt(k-1) - sqrt(k-2))/(1 + sqrt((k-1)*(k-2)))) > 0, for k >= 3. Therefore the conjecture is that delta(k) < 2*Pi*(1 - frac(phi(k)/(2*Pi))), for k >= 3, or, equivalently, phihat(k-2) < 2*Pi*(K(k) + 1), for k >= 3.
%D A295339 P. J. Davis, Spirals from Theodorus to Chaos, A K Peters, Wellesley, MA, 1993.
%H A295339 Joerg Waldvogel, <a href="http://www.sam.math.ethz.ch/~joergw/Papers/theopaper.pdf">Analytic Continuation of the Theodorus Spiral</a>.
%F A295339 a(n) = -1 + first position of n in the sequence
%F A295339   Khat:= {floor(phihat(k)/(2*Pi))}_{ k>= 1}, with phihat given in a comment above in terms of phi.
%F A295339 Conjecture: a(n) = A072895(n) - 2, n >= 1 (see the comment above).
%Y A295339 Cf. A072895 (outer spiral), A296179.
%K A295339 nonn
%O A295339 1,1
%A A295339 _Wolfdieter Lang_, Dec 13 2017