cp's OEIS Frontend

A296292 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + n*b(n-1), where a(0) = 2, a(1) = 4, b(0) = 1, b(1) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.

%I A296292 #4 Dec 14 2017 14:23:10
%S A296292 2,4,12,31,67,133,248,444,772,1315,2217,3686,6083,9977,16298,26545,
%T A296292 43147,70032,113557,184007,298024,482535,781109,1264242,2045999,
%U A296292 3310941,5357694,8669445,14028035,22698437,36727492,59427014,96155658,155583893,251740843
%N A296292 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + n*b(n-1), where a(0) = 2, a(1) = 4, b(0) = 1, b(1) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
%C A296292 The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. a(n)/a(n-1) -> (1 + sqrt(5))/2 = golden ratio (A001622). See A296245 for a guide to related sequences.
%H A296292 Clark Kimberling, <a href="/A296292/b296292.txt">Table of n, a(n) for n = 0..1000</a>
%H A296292 Clark Kimberling, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL10/Kimberling/kimberling26.html">Complementary equations</a>, J. Int. Seq. 19 (2007), 1-13.
%e A296292 a(0) = 2, a(1) = 4, b(0) = 1, b(1) = 3, b(2) = 5
%e A296292 a(2) = a(0) + a(1) + 2*b(1) = 12
%e A296292 Complement: (b(n)) = (1, 3, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 16, ...)
%t A296292 a[0] = 2; a[1] = 4; b[0] = 1; b[1] = 3;
%t A296292 a[n_] := a[n] = a[n - 1] + a[n - 2] + n*b[n-1];
%t A296292 j = 1; While[j < 10, k = a[j] - j - 1;
%t A296292  While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
%t A296292 Table[a[n], {n, 0, k}]; (* A296292 *)
%t A296292 Table[b[n], {n, 0, 20}]    (* complement *)
%Y A296292 Cf. A001622, A296245.
%K A296292 nonn,easy
%O A296292 0,1
%A A296292 _Clark Kimberling_, Dec 14 2017