A297126 Numbers whose base-3 digits d(m), d(m-1),..., d(0) have m=0 or else d(i) = d(i+1) for some i in {0,1,...,m-1}.
1, 2, 4, 8, 9, 12, 13, 14, 17, 18, 22, 24, 25, 26, 27, 28, 29, 31, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 49, 51, 52, 53, 54, 55, 56, 58, 62, 63, 66, 67, 68, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 93, 94, 95
Offset: 1
Examples
Base-3 digits of 95: 1,0,1,1,2, so that 95 is in the sequence.
Links
- Robert Israel, Table of n, a(n) for n = 1..10000
Programs
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Maple
filter:= proc(n) local L; L:= convert(n,base,3); member(0,L[2..-1]-L[1..-2]) end proc: filter(1):= true: filter(2):= true: select(filter, [$1..100]); # Robert Israel, Apr 12 2018
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Mathematica
a[n_, b_] := Sign[Differences[IntegerDigits[n, b]]]; z = 300; b = 3; t = Table[a[n, b], {n, 1, 10*z}]; u = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == 1 &] (* A297124 *) v = Select[Range[z], ! MemberQ[t[[#]], 0] && First[t[[#]]] == -1 &] (* A297125 *) Complement[Range[z], Union[u, v]] (* A297126 *)
Extensions
3 removed by Robert Israel, Apr 12 2018
Comments