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A299238 a(n) = the index m satisfying t(m) = 5 - t(n), where t(n) is the n-th {2,3}-power tower; see Comments.

%I A299238 #18 Nov 24 2024 03:27:14
%S A299238 2,1,7,5,4,16,3,15,12,11,10,9,34,33,8,6,32,31,26,25,24,23,22,21,20,19,
%T A299238 70,69,68,67,18,17,14,13,66,65,64,63,54,53,52,51,50,49,48,47,46,45,44,
%U A299238 43,42,41,40,39,142,141,140,139,138,137,136,135,38,37,36
%N A299238 a(n) = the index m satisfying t(m) = 5 - t(n), where t(n) is the n-th {2,3}-power tower; see Comments.
%C A299238 Suppose that S is a set of real numbers. An S-power-tower, t, is a number t = x(1)^x(2)^...^x(k), where k >= 1 and x(i) is in S for i = 1..k. We represent t by (x(1), x(2), ..., x(k)), which for k > 1 is defined as (x(1), (x(2), ..., x(k))); (2,3,2) means 2^9. The number k is the *height* of t. If every element of S exceeds 1 and all the power towers are ranked in increasing order, the position of each in the resulting sequence is its *rank*. See A299229 for a guide to related sequences.
%C A299238 This sequence is a self-inverse permutation of the positive integers.
%H A299238 Clark Kimberling, <a href="/A299238/b299238.txt">Table of n, a(n) for n = 1..1000</a>
%e A299238 t(12) = (3,3,2) and t(9) = (2,2,3) = 5 - (3,3,2), so that a(12) = 9. (Note: 5 - (x(1), x(2), ..., x(k)) means (5-x(1), 5-x(2), ..., 5-x(k))).
%t A299238 t[1] = {2}; t[2] = {3}; t[3] = {2, 2}; t[4] = {2, 3}; t[5] = {3, 2};
%t A299238 t[6] = {2, 2, 2}; t[7] = {3, 3}; t[8] = {3, 2, 2}; t[9] = {2, 2, 3};
%t A299238 t[10] = {2, 3, 2}; t[11] = {3, 2, 3}; t[12] = {3, 3, 2};
%t A299238 z = 190; g[k_] := If[EvenQ[k], {2}, {3}]; f = 6;
%t A299238 While[f < 13, n = f; While[n < z, p = 1;
%t A299238   While[p < 12, m = 2 n + 1; v = t[n]; k = 0;
%t A299238     While[k < 2^p, t[m + k] = Join[g[k], t[n + Floor[k/2]]]; k = k + 1];
%t A299238    p = p + 1; n = m]]; f = f + 1]
%t A299238 Flatten[Table[Select[Range[1000], t[#] == 5 - t[n] &], {n, 1, 150}]] (* A299238 *)
%Y A299238 Cf. A299229.
%K A299238 nonn,easy
%O A299238 1,1
%A A299238 _Clark Kimberling_, Feb 07 2018