A299595 T(n,k)=Number of nXk 0..1 arrays with every element unequal to 0, 1 or 4 horizontally, vertically or antidiagonally adjacent elements, with upper left element zero.
1, 2, 2, 3, 1, 3, 5, 3, 3, 5, 8, 5, 5, 5, 8, 13, 8, 11, 11, 8, 13, 21, 15, 19, 23, 19, 15, 21, 34, 26, 35, 53, 53, 35, 26, 34, 55, 45, 65, 121, 113, 121, 65, 45, 55, 89, 80, 120, 250, 256, 256, 250, 120, 80, 89, 144, 140, 220, 533, 541, 576, 541, 533, 220, 140, 144, 233, 245
Offset: 1
Examples
Some solutions for n=5 k=4 ..0..0..1..0. .0..1..0..0. .0..1..0..0. .0..0..0..0. .0..0..0..0 ..0..0..0..0. .0..0..0..0. .0..0..0..0. .0..0..0..1. .1..0..0..0 ..0..0..0..0. .0..0..0..0. .0..0..0..1. .0..0..0..0. .0..0..0..0 ..1..0..0..1. .1..0..0..0. .1..0..0..0. .1..0..0..0. .0..0..0..1 ..0..0..0..0. .0..0..0..0. .0..0..0..0. .0..0..1..0. .0..0..0..0
Links
- R. H. Hardin, Table of n, a(n) for n = 1..9934
Formula
Empirical for diagonal: [linear recurrence of order 15] for n>18
Empirical for column k:
k=1: a(n) = a(n-1) +a(n-2)
k=2: a(n) = a(n-1) +2*a(n-3) +a(n-5) for n>6
k=3: a(n) = a(n-1) +2*a(n-3) +a(n-4) +a(n-5) for n>8
k=4..99: a(n) = a(n-1) +a(n-2) +3*a(n-3) +a(n-4) -a(n-5) -a(n-6) for n>9
Comments