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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A300903 a(n) is the smallest k such that k^2 - n^2 is a prime power (A000961), or 0 if no such k exists.

Original entry on oeis.org

1, 2, 3, 4, 5, 6, 7, 9, 9, 10, 15, 12, 13, 14, 15, 16, 48, 0, 19, 0, 21, 22, 0, 24, 25, 0, 27, 54, 36, 30, 31, 33, 96, 34, 0, 36, 37, 0, 0, 40, 41, 42, 0, 0, 45, 0, 0, 0, 49, 0, 51, 52, 0, 54, 55, 66, 57, 0, 0, 0, 61, 0, 63, 64, 192, 66, 0, 0, 69, 70, 0, 0, 0, 0, 75, 76, 0, 0, 79, 0, 0, 82, 0, 84, 85, 0, 87, 0, 0, 90, 91, 0, 0, 0, 0, 96, 97
Offset: 0

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Author

Altug Alkan, Mar 14 2018

Keywords

Comments

If such k exists (for n > 0), then the maximum ratio of k / n is (p + 1)/(p - 1) with p = 2 where p is prime root of corresponding prime power. So a(n) <= 3*n.
If 2*n+1 is in A000961 (in particular if n is in A005097), then a(n) = n + 1.
Numbers n such that a(n) = 0 are 17, 19, 22, 25, 34, 37, 38, 42, 43, 45, 46, ...
Initial corresponding prime powers are 1, 3, 5, 7, 9, 11, 13, 32, 17, 19, 125, 23, 25, 27, 29, 31, 2048.

Examples

			a(17) = 0 because there is no k such that k^2 - 17^2 = (k + 17)*(k - 17) is a prime power.
a(21) = 22 because 22^2 - 21^2 = 43 and 22 is the least number with this property.
a(27) = 54 because 54^2 - 27^2 = 3^7 and 54 is the only number with this property.
		

Crossrefs

Programs

  • Maple
    f:= proc(n) local p,k,a,b,r;
      if nops(numtheory:-factorset(2*n+1))<=1 then return n+1 fi;
      k:= infinity;
      for p in numtheory:-factorset(2*n) do
        b:= padic:-ordp(2*n,p);
        r:= 2*n + p^b;
        a:= padic:-ordp(r,p);
        if r = p^a then
          k:= min(k, (p^a+p^b)/2)
        fi
      od;
      if k = infinity then 0 else k fi
    end proc:
    map(f, [$0..1000]); # Robert Israel, Mar 15 2018
  • Mathematica
    Table[Boole[n == 0] + Block[{k = n + 1, m = 3 n}, While[Nor[PrimePowerQ[k^2 - n^2], k > m], k++]; If[k > m, 0, k]], {n, 0, 96}] (* Michael De Vlieger, Mar 16 2018 *)
  • PARI
    a(n) = if(n==0, 1, for(k=n+1, 3*n, if(isprimepower(k^2-n^2), return(k)));0)