cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A365902 Irregular triangle of highly composite numbers h(n) = A002182(n) arranged first according to rad(h(n))/h(n) then by rad(h(n)), where rad(n) = A007947(n).

Original entry on oeis.org

1, 2, 6, 4, 12, 60, 24, 120, 840, 36, 180, 1260, 48, 240, 1680, 360, 2520, 27720, 720, 5040, 55440, 720720, 7560, 83160, 1081080, 10080, 110880, 1441440, 15120, 166320, 2162160, 36756720, 698377680, 20160, 221760, 2882880, 25200, 277200, 3603600, 61261200, 332640
Offset: 1

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Author

Michael De Vlieger, Oct 12 2023

Keywords

Comments

rad(h(n)) = P(omega(h(n))), where P(n) = A002110(n) and omega(n) = A001221(n).
This sequence merely lists terms in row n, it does not reflect S(n,j) = A301414(n)*P(j), where P(j) = rad(A301414(n)*P(j)), since least j > 0 for n > 1.

Examples

			Row 1 contains the products of A301414(1) = 1 and each of P(0) = 1, P(1) = 2, and P(2) = 6.
Row 2 contains the products of A301414(2) = 2 and each of P(1), P(2), and P(3) = 30.
Row 3 contains the products of A301414(3) = 4 and each of P(2) and P(3), etc.
Table of first rows of S(n,j), where for S(n,j) = A002182(i), j = A108602(i):
  n\j | 0  1   2    3     4       5
  ----------------------------------
    1 | 1, 2,  6
    2 |    4, 12,  60
    3 |       24, 120
    4 |       36, 180, 1260
    5 |       48, 240, 1680
    6 |           360, 2520,  27720
    7 |           720, 5040, 720720, etc.
In this sequence T(n,k) we have the following:
1: 1, 2, 6;
2: 4, 12, 60;
3: 24, 120;
4: 36, 180, 1260;
5: 48, 240, 1680;
6: 360, 2520, 27720;
7: 720, 5040, 720720; etc.
		

Crossrefs

Programs

  • Mathematica
    nn = 8; rad[x_] := rad[x] = Times @@ FactorInteger[x][[All, 1]];
    MapIndexed[Set[P[First[#2]], #1] &, FoldList[Times, Prime@ Range[nn + 1]]];
    a2182 = Import["https://oeis.org/A002182/b002182.txt", "Data"][[All, -1]];
    TakeWhile[
       SplitBy[SortBy[
         Map[{#1/#2, PrimeNu[#2], #1} & @@ {#, rad[#]} &,
          TakeWhile[a2182, rad[#] <= P[nn] &]], #[[1 ;; 2]] &,
         LexicographicOrder], First],
       FreeQ[a2182, #1 P[#2 + 1]] & @@ #[[-1, 1 ;; 2]] &][[All, All, -1]] // Flatten

Formula

Let i = least j such that A301414(n)*A002110(j) is in A002182.
This sequence is T(n,k) = S(n,j-i+1).
Length of row n = A301415(n).
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