cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A306537 The least prime q such that Kronecker(D/q) = 1 where D runs through all positive fundamental discriminants (A003658).

Original entry on oeis.org

2, 11, 7, 11, 3, 2, 5, 5, 3, 5, 2, 3, 3, 2, 5, 7, 5, 2, 7, 3, 2, 5, 2, 3, 13, 3, 3, 2, 7, 7, 2, 5, 5, 2, 3, 2, 7, 3, 2, 3, 3, 2, 13, 5, 2, 5, 11, 5, 3, 2, 7, 11, 3, 13, 2, 3, 3, 2, 11, 2, 7, 2, 5, 3, 2, 11, 2, 3, 5, 3, 3, 2, 5, 13, 2, 13, 2, 3, 2, 5, 2, 3, 5, 2
Offset: 1

Views

Author

Jianing Song, Feb 22 2019

Keywords

Comments

a(n) is the least prime that decomposes in the real quadratic field with discriminant D, D = A003658(n).
For most n, a(n) is relatively small. There are only 459 n's among [1, 3044] (there are 3044 terms in A003658 below 10000) that violate a(n) < log(A003658(n)).
Also a(n) is the smallest prime p such that the real quadratic field with discriminant D = A003658(n) can be embedded into the p-adic field Q_p. - Jianing Song, Feb 14 2021

Examples

			Let K = Q[sqrt(635)] with D = 2540 = A003658(774), we have: 2 and 5 divides 2540, (2540/3) = (2540/7) = ... = (2540/37) = -1 and (2540/41) = +1, so 2 and 5 ramify in K, 3, 7, ..., 37 remain inert in K and 41 decomposes in K, so a(774) = 41.
		

Crossrefs

Cf. A003658.
Similar sequences: A232931, A232932 (the least prime that remains inert); this sequence, A306538 (the least prime that decomposes); A306541, A306542 (the least prime that decomposes or ramifies).

Programs

  • PARI
    b(D)=forprime(p=2, oo, if(kronecker(D, p)>0, return(p)))
    for(n=1, 300, if(isfundamental(n), print1(b(n), ", ")))

A306541 The least prime q such that Kronecker(D/q) >= 0 where D runs through all positive fundamental discriminants (A003658).

Original entry on oeis.org

2, 5, 2, 2, 3, 2, 3, 2, 2, 5, 2, 3, 2, 2, 2, 7, 2, 2, 2, 3, 2, 3, 2, 2, 7, 3, 2, 2, 2, 3, 2, 5, 2, 2, 3, 2, 2, 2, 2, 3, 2, 2, 2, 3, 2, 5, 2, 2, 3, 2, 3, 2, 2, 13, 2, 3, 2, 2, 2, 2, 7, 2, 2, 3, 2, 3, 2, 2, 5, 3, 2, 2, 2, 3, 2, 2, 2, 3, 2, 2, 2, 2, 5, 2, 3, 2, 2, 2
Offset: 1

Views

Author

Jianing Song, Feb 22 2019

Keywords

Comments

a(n) is the least prime that either decomposes or ramifies in the real quadratic field with discriminant D, D = A003658(n).
For most n, a(n) is relatively small. There are only 86 n's among [1, 3044] (there are 3044 terms in A003658 below 10000) that violate a(n) < log(A003658(n)).

Examples

			Let K = Q[sqrt(293)] with D = 293 = A003658(90), we have: (293/2) = (293/3) = ... = (293/13) = -1 and (293/17) = +1, so 2, 3, 5, 7, 11 and 13 remain inert in K and 17 decomposes in K, so a(90) = 17.
		

Crossrefs

Cf. A003658.
Similar sequences: A232931, A232932 (the least prime that remains inert); A306537, A306538 (the least prime that decomposes); this sequence, A306542 (the least prime that decomposes or ramifies).

Programs

  • PARI
    b(D)=forprime(p=2, oo, if(kronecker(D, p)>=0, return(p)))
    for(n=1, 300, if(isfundamental(n), print1(b(n), ", ")))

A306542 The least prime q such that Kronecker(D/q) >= 0 where D runs through all negative fundamental discriminants (-A003657).

Original entry on oeis.org

3, 2, 2, 2, 3, 2, 5, 2, 2, 2, 2, 3, 2, 2, 11, 2, 3, 2, 2, 2, 3, 17, 2, 2, 2, 3, 2, 2, 2, 5, 2, 2, 2, 3, 2, 5, 2, 2, 2, 3, 2, 3, 2, 2, 5, 2, 2, 2, 2, 3, 2, 41, 2, 2, 2, 3, 2, 2, 7, 2, 3, 2, 3, 5, 2, 2, 3, 2, 3, 2, 2, 2, 5, 2, 2, 2, 2, 3, 2, 5, 2, 2, 2, 3, 2, 2, 2, 7
Offset: 1

Views

Author

Jianing Song, Feb 22 2019

Keywords

Comments

a(n) is the least prime that either decomposes or ramifies in the imaginary quadratic field with discriminant D, D = -A003657(n).
The quadratic field with discriminant D = -A003657(n) has class number 1 if and only if a(n) >= (1/4)*A003657(n). If the quadratic field with discriminant D = -A003657(n) has class number 3 then a(n)^2 < (1/4)*A003657(n) < a(n)^3.
For most n, a(n) is relatively small. There are only 86 n's among [1, 3043] (there are 3043 terms in A003657 below 10000) that violate a(n) < log(A003657(n)). In fact, if we ignore the first term, the only terms among the first 3043 ones that seem unusually large are a(15) = 11 (with A003657(15) = 43), a(22) = 17 (with A003657(22) = 67), a(52) = 41 (with A003657(52) = 163), a(1147) = 23 (with A003657(1147) = 3763), a(2677) = 23 (with A003657(2677) = 8803) and a(2758) = 23 (with A003657(2758) = 9067).

Examples

			Let K = Q[sqrt(-3763)] with D = -3763 = -A003657(1147), we have: (-3763/2) = (-3763/3) = ... = (-3763/19) = -1 and (-3763/23) = +1, so 2, 3, 5, 7, 11, 13, 17 and 19 remain inert in K and 23 decomposes in K, so a(1147) = 23.
		

Crossrefs

Cf. A003657.
Similar sequences: A232931, A232932 (the least prime that remains inert); A306537, A306538 (the least prime that decomposes); A306541, this sequence (the least prime that decomposes or ramifies).

Programs

  • PARI
    b(D)=forprime(p=2, oo, if(kronecker(D, p)>=0, return(p)))
    for(n=1, 300, if(isfundamental(-n), print1(b(-n), ", ")))

A330162 For imaginary fundamental discriminants -d, define b(-d) to be the smallest prime p such that Kronecker(-d,p) = 1. Sequence gives d such that b(-d)^3 > d/4 > b(-d)^2.

Original entry on oeis.org

23, 31, 56, 59, 68, 83, 104, 107, 136, 139, 184, 211, 219, 244, 259, 264, 276, 283, 291, 292, 307, 328, 331, 339, 355, 376, 379, 388, 411, 424, 436, 451, 456, 472, 499, 523, 547, 552, 568, 580, 628, 643, 667, 712, 723, 763, 772, 787, 808, 820, 835, 843, 852, 868, 883
Offset: 1

Views

Author

Jianing Song, Dec 04 2019

Keywords

Comments

It seems that this sequence contains 810 terms, the largest being 1154008. In general, it seems that for any t > 0, b(-d) = o(d^t) as -d -> -oo.
For fundamental discriminants -d, we want to determine the size of b(-d), i.e., the size of the smallest prime that decomposes in Q[sqrt(-d)].
Let K = Q[sqrt(-d)], O_K be the ring of integers over K, so O_K is a Dedekind domain. Let E(-d) be the exponent of the ideal class group of O_K (the exponent of a group G is the smallest e > 0 such that x^e = I for all x in G, where I is the group identity).
If Kronecker(-d,p) = 1, it is well-known that p*O_K is the product of two distinct prime ideals of O_K, say, p*O_K = I*I'. By the property of the ideal class group of Q[sqrt(-d)], I^(k*e) must be principal, e = E(-d). Let t*O_K = I^(k*e), then t/p is not an algebraic integer, and the norm of t is p^e. Define f(x,y) = x^2 + (d/4)*y^2 if -d == 0 (mod 4), x^2 + x*y + ((d+1)/4)*y^2 otherwise, it is easy to see f(x,y) = p^(k*e) has integral solutions (x,y) such that gcd(x,y) = 1.
If f(x,y) = p^(k*e) < d, then |y| = 1, so 4*p^(k*e) - d must be a (positive) square. Setting k = 1 gives b(-d) > (d/4)^(1/e) (and furthermore we have: if Kronecker(-d,p) = 1 and p^(k*e) < d, then k = 1, or (p,k,e,d) = (2,2,1,7), (3,2,1,11)).
If E(-d) = 3, then d is in this sequence.
We also have the following observations (not proved):
(a) if e = 2 (i.e., d is in A003644\A014602 = A316743), then b(-d) < d/4;
(b) if e > 2, then b(-d) < sqrt(d/4) (it can be proved by using deeper algebraic number theory that b(-d) < 2*sqrt(d)/Pi).
If these observations are true, this sequence is also the list of d such that b(-d) > (d/4)^(1/3) and d is not in A003644.
Note that 5460 is conjectured to be the largest term in A003644. Therefore, it seems that b(-d) < sqrt(d/4) for all d > 5460; it seems that b(-d) < (d/4)^(1/3) for all d > 1154008.
Among the known terms:
(1) the term d with the largest E(-d) is d = 998328 with E(-d) = 66.
(2) the term d with the largest b(-d) is d = 656755 with b(-d) = 79.
(3) the largest prime is d = 90787 with E(-d) = 23.

Examples

			The smallest prime p such that Kronecker(-499,p) = 1 is p = 5, and 5^3 > 499/4 > 5^2, so 499 is a term.
		

Crossrefs

Programs

  • PARI
    b(D)=forprime(p=2, oo, if(kronecker(D, p)>0, return(p)))
    isA330162(d) = (d>0) && isfundamental(-d) && b(-d) > sqrtn(d/4,3) && b(-d) < sqrt(d/4)

A330161 Fundamental discriminant D < 0 with the least absolute value such that the smallest prime p such that Kronecker(D,p) = 1 is p = prime(n), negated.

Original entry on oeis.org

7, 8, 4, 3, 43, 88, 67, 148, 267, 760, 232, 1320, 163, 1848, 45208, 124195, 169603, 85507, 121972, 261627, 424708, 656755, 35230603, 80149435, 154962808, 289615747
Offset: 1

Views

Author

Jianing Song, Dec 03 2019

Keywords

Comments

If a(n) < (Pi*prime(n)/2)^2 (this occurs for n <= 14), then the ideal class group of Q[sqrt(-d)] necessarily has exponent <= 2. (The exponent of a group G is the smallest e > 0 such that x^e = I for all x in G, where I is the group identity.) See A330221.
It seems that lim_{n->oo} n^t/a(n) = 0 for all t > 0.
The exponent of the ideal class group of Q[sqrt(-a(n))]: 1, 1, 1, 1, 1, 2, 1, 2, 2, 2, 2, 2, 1, 2, 26, 16, 36, 22, 38, 24, 16, 36, 104, 388, 104, 288, ...

Examples

			D = -1848 is the fundamental discriminant D < 0 with the least absolute value such that Kronecker(D,p) <= 0 for p = 2, 3, 5, 7, ..., 41 and Kronecker(D,43) = +1, so a(14) = 1848.
		

Crossrefs

Programs

  • PARI
    b(D)=forprime(p=2, oo, if(kronecker(D, p)>0, return(p)))
    a(n)=my(p=prime(n)); for(D=3, oo, if(isfundamental(-D) && b(-D)==p, return(D)))
Showing 1-5 of 5 results.